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horrorfan [7]
3 years ago
14

The following slide was created as part of a presentation that trains new employees how to use the scheduling and calendar softw

are. Each item in the bulleted list files in from the bottom of the screen.does this slide follow the guidelines for animation and multimedia? Yes no ?
Computers and Technology
2 answers:
brilliants [131]3 years ago
8 0

it has animation, but it does not have multimedia and only has text and no images

zavuch27 [327]3 years ago
8 0

Answer:

Yes.

Explanation:

Microsoft PowerPoint is a presentation application, in Microsoft office packages. The slides in the documents are used to present text or graphical data. To progress to the next slide, the direction arrow key is pressed or a click on the side of the slide.

To automatically change slides at a time interval or introduce various components on the same slide, the animate function is used.

In the question, when the list moves in from the bottom, it is animated to the screen.

Animation and multimedia guidelines like the duration and positioning of the list in the slide are accounted for.

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Which Access database object asks a question about the data stored in a database and displays specific fields and records that a
AVprozaik [17]

Answer: Query

Explanation:

It is through the process of queries a user is able to ask questions about the data stored in the database and view specific fields as required. These queries can be of many type and each time using a query would give us the desired fields.

7 0
3 years ago
What is the output of this code? import java.util.HashSet; class A { public static void main(String[ ] args) { HashSet set = new
kompoz [17]

Answer:

The code will give an error that is "At least one public class is required in main file".

Explanation:

In the given code if we do not use the public access modifier to the class. It will give an error so, the correct code to this question as follows:

Program:

import java.util.HashSet; //import package

public class A  //define class as public.

{

   public static void main(String[ ] args) //define main method.

   {

       HashSet set = new HashSet(); //creating hashset object.

       set.add("A"); //add alphabet in hashset

       set.add("B"); //add alphabet in hashset

       set.add("C"); //add alphabet in hashset

       System.out.print("Size of HashSet is :"set.size()); //print the size of hashset.

   }

}

Output:

Size of HashSet is : 3

Explanation of the program:  

  • In the above program, we define a public class that is "A" and inside the class, we define the main method.  
  • Inside the main method, we create a HashSet class object that is "set".  
  • To add elements in HashSet we use add() function that adds elements and in the last, we use the size() function that prints the size HashSet.
5 0
3 years ago
Question 2 of 10
Roman55 [17]

Answer:

C

Explanation:

correct answer

3 0
3 years ago
There will be 10 numbers stored contiguously in the computer at location x 7000 . Write a complete LC-3 program, starting at loc
Artist 52 [7]

Answer:

The LC-3 (Little Computer 3) is an ISA definition for a 16-bit computer. Its architecture includes physical memory mapped I/O via a keyboard and display; TRAPs to the operating system for handling service calls; conditional branches on N, Z, and P condition codes; a subroutine call/return mechanism; a minimal set of operation instructions (ADD, AND, and NOT); and various addressing modes for loads and stores (direct, indirect, Base+offset, PC-relative, and an immediate mode for loading effective addresses). Programs written in LC-3 assembler execute out of a 65536 word memory space. All references to memory, from loading instructions to loading and storing register values, pass through the get Mem Adr() function. The hardware/software function of Project 5 is to translate virtual addresses to physical addresses in a restricted memory space. The following is the default, pass-through, MMU code for all memory references by the LC-3 simulator.

unsigned short int get Mem Adr(int va, int rwFlg)

{

unsigned short int pa;

// Warning: Use of system calls that can cause context switches may result in address translation failure

// You should only need to use gittid() once which has already been called for you below. No other syscalls

// are necessary.

TCB* tcb = get TCB();

int task RPT = tcb [gettid()].RPT;

pa = va;

// turn off virtual addressing for system RAM

if (va < 0x3000) return &memory[va];

return &memory[pa];

} // end get MemAdr

Simple OS, Tasks, and the LC-3 Simulator

We introduce into our simple-os a new task that is an lc3 Task. An lc3 Task is a running LC-3 simulator that executes an LC-3 program loaded into the LC-3 memory. The memory for the LC-3 simulator, however, is a single global array. This single global array for memory means that alllc3 Tasks created by the shell use the same memory for their programs. As all LC-3 programs start at address 0x3000 in LC-3, each task overwrites another tasks LC-3 program when the scheduler swaps task. The LC-3 simulator (lc3 Task) invokes the SWAP command every several LC-3 instruction cycles. This swap invocation means the scheduler is going to be swapping LC-3 tasks before the tasks actually complete execution so over writing another LC-3 task's memory in the LC-3 simulator is not a good thing.

You are going to implement virtual memory for the LC-3 simulator so up to 32 LC-3 tasks can be active in the LC-3 simulator memory without corrupting each others data. To implement the virtual memory, we have routed all accesses to LC-3 memory through a get Mem Adr function that is the MMU for the LC-3 simulator. In essence, we now have a single LC-3 simulator with a single unified global memory array yet we provide multi-tasking in the simulator for up to 32 LC-3 programs running in their own private address space using virtual memory.

We are implementing a two level page table for the virtual memory in this programming task. A two level table relies on referring to two page tables both indexed by separate page numbers to complete an address translation from a virtual to a physical address. The first table is referred to as the root page table or RPT for short. The root page table is a fixed static table that always resides in memory. There is exactly one RPT per LC-3 task. Always.

The memory layout for the LC=3 simulator including the system (kernel) area that is always resident and non-paged (i.e., no virtual address translation).

The two figures try to illustrate the situation. The lower figure below demonstrates the use of the two level page table. The RPT resident in non-virtual memory is first referenced to get the address of the second level user page table or (UPT) for short. The right figure in purple and green illustrates the memory layout more precisely. Anything below the address 0x3000 is considered non-virtual. The address space is not paged. The memory in the region 0x2400 through 0x3000 is reserved for the RPTs for up to thirty-two LC-3 tasks. These tables are again always present in memory and are not paged. Accessing any RPT does not require any type of address translation.

The addresses that reside above 0x3000 require an address translation. The memory area is in the virtual address space of the program. This virtual address space means that a UPT belonging to any given task is accessed using a virtual address. You must use the RPT in the system memory to keep track of the correct physical address for the UPT location. Once you have the physical address of the UPT you can complete the address translation by finding the data frame and combining it with the page offset to arrive at your final absolute physical address.

A Two-level page table for virtual memory management.

x7000 123F x7000 0042

x7001 6534 x7001 6534

x7002 300F x7002 300F

x7003 4005 after the program is run, memory x7003 4005

x7004 3F19

7 0
3 years ago
Read 2 more answers
Which line of code will create an instance of the pet class?
Sunny_sXe [5.5K]

Answer:

myPetA = pet(self, 'dog', 'Spot')

Explanation:

I mite be wrong

8 0
3 years ago
Read 2 more answers
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