1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alexeev081 [22]
3 years ago
8

Describe at least one reason why transitioning from the Cisco implementation of STP to the Cisco implementation of RSTP is seaml

ess and state why an administrator would want to make the change.
Computers and Technology
1 answer:
kherson [118]3 years ago
6 0

Answer:

STP mainly uses 5 states in a network, in which some states are replaced in RSTP which improves the time efficiency.

Explanation:

STP mainly uses five states i.e.  Learning, Listening, Blocking, Disabling and Forwarding to overcome the problem of collision in a network.  

RSTP replaced the three states of STP i.e listening, learning, and blocking by Discarding, which results in the time efficiency as compared to STP.  

As STP takes minutes to complete the network inter connectivity, RSTP completes it in seconds.

This is one of the main reason why an administrator want to change to RSTP.

You might be interested in
Consider a disk with the following characteristics (these are not parameters of any particular disk unit): block size B 512 byte
telo118 [61]

Answer:

a) total capacity = (Block size + I. Gap size)*N

total capacity = (512+128 Bytes)* 20= 12800 Bytes = 12.8 Kb

Useful.cap = Block size * N = 512*20 = 10240 Bytes = 10.24 Hb

b) Cylinders c) [tex] T = (512+128 Gb) *20 *15*2 = 384000 Bytes= 384Kb

U = 512Gb*20*15*2= 307200 Bytes= 307.2 Kb

d) TS= 384000 Bytes *400 =153600000 Bytes= 153500 Kb= 153. 6Mb

UT = 307200 Bytes*400=122880000 Bytes = 122880 Kb = 122.88 Mb

e) RS= 2400 rpm * \frac{60 s}{1 min}= 144000 rps

Tr= \frac{total capacity}{RS} = \frac{12800 By}{144000 rps}= 0.0889 bytes/s

And if we convert using 1 s = 1000 ms we have"

0.0889 bytes/s * 1000 =88.89 bytes/ms

The block transfer time btt would be given by:

btt= \frac{512 bytes}{88.9 bytes/ms}=5.76 ms

And the average rotational delay would be given by:

rd= \frac{1}{2} (\frac{1}{2400 rpm}) 60 s  \frac{1000 ms}{1 s}= 12.5 ms

f) For this case we can calculate the average time to locate and transfer adding the following time:

TT= btt +rd+ st = 5.76 +12.5 +30 ms= 48.26 ms

g) For this case we can calculate the time to transfer 20 random blocks like this:

t_1 = 20*(s+rd+btt) = 20*(30+12.5+5.76) =965.2 ms

And the time to transfer 20 consecutive blocks using double buffering would be:

t_2 = s+ rd+ 20 btt = 30 +12.5 + 20 (5.76)=157.7 ms

Explanation:

Part a

For this case we need to calculate first the total capcity like this:

total capacity = (Block size + I. Gap size)*N

Where N represent the number of blocs per track, and if we replace we got:

total capacity = (512+128 Bytes)* 20= 12800 Bytes = 12.8 Kb

And the useful capacity is given by:

Useful.cap = Block size * N = 512*20 = 10240 Bytes = 10.24 Hb

Part b

For this case the number of cylinders correspond to the number of tracks.

Cylinders = tracks= 400

Part c

First we can calculate the total cylinder capacity like this:

T = (512+128 Gb) *20 *15*2 = 384000 Bytes= 384Kb

And the useful capacity is:

U = 512Gb*20*15*2= 307200 Bytes= 307.2 Kb

Part d

We can calculate the totals like on part d but we just need to multiply by 400 since that represent the number of tracks per surface

TS= 384000 Bytes *400 =153600000 Bytes= 153500 Kb= 153. 6Mb

UT = 307200 Bytes*400=122880000 Bytes = 122880 Kb = 122.88 Mb

Part e

For this case we can convert the revolution per minute in revolutions per second like this:

RS= 2400 rpm * \frac{60 s}{1 min}= 144000 rps

And we can calculate the transfer rate like this:

Tr= \frac{total capacity}{RS} = \frac{12800 By}{144000 rps}= 0.0889 bytes/s

And if we convert using 1 s = 1000 ms we have"

0.0889 bytes/s * 1000 =88.89 bytes/ms

The block transfer time btt would be given by:

btt= \frac{512 bytes}{88.9 bytes/ms}=5.76 ms

And the average rotational delay would be given by:

rd= \frac{1}{2} (\frac{1}{2400 rpm}) 60 s \frac{1000 ms}{1 s}= 12.5 ms

Part f

For this case we can calculate the average time to locate and transfer adding the following time:

TT= btt +rd+ st = 5.76 +12.5 +30 ms= 48.26 ms

Part g

For this case we can calculate the time to transfer 20 random blocks like this:

t_1 = 20*(s+rd+btt) = 20*(30+12.5+5.76) =965.2 ms

And the time to transfer 20 consecutive blocks using double buffering would be:

t_2 = s+ rd+ 20 btt = 30 +12.5 + 20 (5.76)=157.7 ms

7 0
3 years ago
I want to make apps but I don't know how and which things I have to learn first ,so if you know mention from starting to ending​
anyanavicka [17]

Answer:

There are a lot to learn, especially the basics. I'd suggest using SolorLearn for this.

6 0
3 years ago
Which category of system software provides a platform for application software to run on?
yanalaym [24]

Operating system is the correct answer

6 0
4 years ago
Read 2 more answers
What tool do you use to secure remote access by users who utilize the internet??
madam [21]
The tool that you use to secure remote access by users is VPN
3 0
3 years ago
What computer part do you need to make you’re pc run faster?
Alisiya [41]
There are multiple things that effect the speed of your computer such as the processer, RAM, and what is on the computer itself. The first question would be to figure out what might be slowing down your computer and the reason for needing the increase in speed. This will tell you what part you need and the steps to take.
3 0
3 years ago
Other questions:
  • The efficiency of a screw is low because of _____. width friction length height
    10·2 answers
  • The Occupational Outlook Handbook is published by the Bureau of Labor Statistics.
    10·2 answers
  • we studied FIFO, Priority, Round Robin (RR), and Weighted Fair Queueing (WFQ) packet scheduling disciplines. Which of these queu
    12·1 answer
  • Using the Internet comes with certain risks that you should be prepared for. True False​
    11·2 answers
  • During the Inspect and Adapt event, how are reflection, data collection, problem solving, and identification of improvement acti
    5·1 answer
  • ELO 3.6 Which type of iSCSI name requires a registered domain name to generate a unique iSCSI identifier?
    12·1 answer
  • Could you please check my answers to this layout user defined data types
    15·1 answer
  • Any one know??please let me know
    15·2 answers
  • Who is known as the first computer programmer?​
    13·1 answer
  • 7 TH GRADE QUESTION...PLS HELP
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!