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3 years ago

Will Mark The Brainliest. Write an equation of the line graphed in slope-intercept form using the variables x and y.

Mathematics

2 answers:

baherus [9]3 years ago

8 0

Answer:

$\boxed{y=-2x+5}$

Step-by-step explanation:

The equation in slope-intercept form is given by:

$y=mx+c$

where $m$ is the slope and $c$ is the y-intercept.

The given line passes through so many points. We can use any two these points to find the slope of the line.

The line passes through $(x_1,y_1)= (1,3)$ and $(x_2,y_2)=(2,1)$ .

The slope is given by;

$m=\frac{y_2-y_1}{x_2-x_1}$ .

$\Rightarrow m=\frac{1-3}{2-1}$ .

$\Rightarrow m=\frac{-2}{1}=-2$ .

The y-intercept from the graph is $c=5$

Our equation finally becomes;

$y=-2x+5$

asambeis [7]3 years ago

5 0

Answer:

y = -2x+5

Step-by-step explanation:

We have two points so we can find slope

(0,5) and (1,3)

m = (y2-y1)/(x2-x1)

= (3-5)/(1-0)

=-2/1

The slope = -2

We know the y intercept is 5 (This is the point where it crosses the y axis)

The slope intercept from is

y= mx+b where m is the slope and b is the y intercept

y = -2x+5

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Read 2 more answers

Find the particular solution that satisfies the differential equation and the initial condition.

Vesnalui [34]

Answer:

1) $y =4x^2 +7$

2) $y =7s^2 -3s^4 +181$

Step-by-step explanation:

Assuming that our function is $y = f(x)$ for the first case and $y=f(s)$ for the second case.

Part 1

We can rewrite the expression like this:

$\frac{dy}{dx} =8x$

And we can reorder the terms like this:

$dy = 8 x dx$

Now if we apply integral in both sides we got:

$\int dy = 8 \int x dx$

And after do the integrals we got:

$y = 4x^2 +c$

Now we can use the initial condition $y(0) =7$

$7 = 4(0)^2 +c, c=7$

And the final solution would be:

$y =4x^2 +7$

Part 2

We can rewrite the expression like this:

$\frac{dy}{ds} =14s -12s^3$

And we can reorder the terms like this:

$dy = 14s -12s^3 dx$

Now if we apply integral in both sides we got:

$\int dy = \int 14s -12s^3 ds$

And after do the integrals we got:

$y = 7s^2 -3s^4 +c$

Now we can use the initial condition $y(3) =1$

$1 = 7(3)^2 -3(3)^4 +c, c=1-63+243=181$

And the final solution would be:

$y =7s^2 -3s^4 +181$

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