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Assoli18 [71]
3 years ago
13

Will Mark The Brainliest. Write an equation of the line graphed in slope-intercept form using the variables x and y.

Mathematics
2 answers:
baherus [9]3 years ago
8 0

Answer:

\boxed{y=-2x+5}

Step-by-step explanation:

The equation in slope-intercept form is given by:

y=mx+c

where m is the slope and c is the y-intercept.


The given line passes through so many points. We can use any two these points to find the slope of the line.

The line passes through (x_1,y_1)= (1,3) and (x_2,y_2)=(2,1).

The slope is given by;

m=\frac{y_2-y_1}{x_2-x_1}.


\Rightarrow m=\frac{1-3}{2-1}.


\Rightarrow m=\frac{-2}{1}=-2.

The y-intercept from the graph is c=5


Our equation finally becomes;

y=-2x+5




asambeis [7]3 years ago
5 0

Answer:

y = -2x+5

Step-by-step explanation:

We have two points so we can find slope

(0,5)  and (1,3)

m = (y2-y1)/(x2-x1)

   =  (3-5)/(1-0)

   =-2/1

  The slope = -2

We know the y intercept is 5  (This is the point where it crosses the y axis)

The slope intercept from is

y= mx+b  where m is the slope and b is the y intercept

y = -2x+5

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11th grade geometry:
Aliun [14]

Answer:

<em>The perimeter is 72 units and the area is 149 square units.</em>

Step-by-step explanation:

\triangle SBA has coordinates S(15,-8),B(-2,21) and A(0,0)

Using the distance formula.........

Length of side SB = \sqrt{(15+2)^2+(-8-21)^2}= \sqrt{17^2+(-29)^2}= \sqrt{1130}

Length of side BA= \sqrt{(-2)^2+(21)^2}= \sqrt{445}

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So, the perimeter of the triangle will be:  (SB+BA+AS)= \sqrt{1130}+ \sqrt{445}+17 =71.71... \approx 72 units.   <em>(Rounded to the nearest unit)</em>

The height of the triangle for the corresponding base SB is 8.89 units.

<u>Formula for the Area of triangle</u>,  A= \frac{1}{2}(base\times height)

So, the area of the \triangle SBA will be:  \frac{1}{2}(\sqrt{1130}\times 8.89)= 149.42... \approx 149 square units.   <em>(Rounded to the nearest unit)</em>

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