The constant that can be added to
- 3x to form a perfect square trinomial is 
The given expression is
- 3x
To form a perfect square trinomial

The given expression is
- 3x
first we have to add a constant term with it
- 3x + z
By comparing the given expression and the perfect square trinomial

a = x
Similarly
-2ab = 3x
where know a =x
Then,
-2b = 3
b = -3/2
Similarly

= z
9/4 = z
Convert the simple fraction to mixed fraction
9/4 = 
Hence, the constant that can be added to
- 3x to form a perfect square trinomial is 
The complete question is :
Which of the following constants can be added to x2 - 3x to form a perfect square trinomial?
and 
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That may be any kinda right circular cylinder it always contain a net like attachment.
So
- There is a rectangle which is not a square for LSA
- And two bases which are circles
Option D
932 divided by 6 is 155.166666667
1. 35x + 0.15y
=3500x + 15y [multiplying the equation by 100]
= 700x + 3y [dividing the equation by 5]
2. Let x be an even integer
x + (x+2) + (x+2+2)
x+x+2+x+4
3x+6
3. 1/5*(r+7) - 9s
(r+7)/5 - 9s
4. x=cows
y= goats + sheep
x= (y+140)/2