Cos(A-B) = cosAcosB + sinAsinB
<span>
cos(</span>π/2 - θ) = cos(π/2)cosθ + sin(π/2)sinθ
π/2 = 90°
cos(π/2) = cos90° = 0. sin(π/2) = sin90° = 1
cos(π/2 - θ) = cos(π/2)cosθ + sin(π/2)sin<span>θ
</span>
= 0*cosθ + 1*sin<span>θ = </span>sin<span>θ
Therefore </span>cos(π/2 - θ) = sin<span>θ
QED </span>
Answer:
don't know
Step-by-step explanation:
not really sure
Answer:
Step-by-step explanation:r=12cm,h=18cm,v=?
Vol. Of a cylinder=Πr²h
V= Π×12²×18
V= Π×144×18
V=2592Πcm³
With polynomials the degree is the highest power x or whatever the variable is raised to. In this case, the degree is 3 since the highest power x is raised to is x^3
A regular savings account
