Question

Complete the following: (2x +3y)^2 = (2x)^2+2(2x)(3y) +(____)^2

Answer 1

Answer:

Complete function will be  $(2x+3y)^2=(2x)^2+(3y)^2+2\times (2x)\times (3y)$

Step-by-step explanation:

We have given equation $(2x+3y)^2=(2x)^2+2\times (2x)\times (3y)+..........^2$

We have to find the function in place of blank space and complete the function

We know the algebraic equation $(a+b)^2=a^2+b^2+2ab$

So $(2x+3y)^2=(2x)^2+(3y)^2+2\times (2x)\times (3y)$

So in place of blank pace there will be $(3y)^2$

And complete function will be  $(2x+3y)^2=(2x)^2+(3y)^2+2\times (2x)\times (3y)$