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The area of an artist's square canvas can hold 113 square inches of paint. What is the approximate length of one side of the can

xeze [42]

The area of any rectangle is:

A=xy, and a square is just a special rectangle where the two dimensions are equal. x=y=s, where s is the side length so the area of a square is:

A=s^2 we want to solve for s so

s^2=A

s=√A, and we are told that the area is 113 in^2

s=√113 in

s≈10.63 in (to nearest hundredth of an inch)

5 0

3 years ago

1. What angles are<br> congruent to angle 5?

Readme [11.4K]

Answer:

All angles that are either exterior angles, interior angles, alternate angles or corresponding angles are all congruent. The picture above shows two parallel lines with a transversal. The angle 6 is 65°. Is there any other angle that also measures 65° hope this helps you

Step-by-step explanation:

8 0

3 years ago

A researcher obtained M = 27 for a sample of n = 36 scores selected from a population with µ = 30 and σ = 18. This sample mean c

dusya [7]

Answer:

True

Step-by-step explanation:

Given that:

M = 27, sample of n = 36 scores, µ = 30 and σ = 18.

The z score is used in statistics to determine by how many standard deviations the raw score is above or below the mean. If the z score is positive, the raw score is greater than the mean and if the z score is negative the raw score is less than the mean. The z score is given as:

$z=\frac{x-\mu}{\sigma}$

Given that M = 27, this means that x = 27. Therefore:

$z=\frac{x-\mu}{\sigma}\\\\for \ a\ sample\ size(n):z=\frac{x-\mu}{\sigma/\sqrt{n} }\\\\z=\frac{27-30}{18/\sqrt{36} } =\frac{-3}{3}=-1$

This sample mean corresponds to a z-score of z = –1.00.

7 0

3 years ago

What is the distance between the points (7, −10) and (−8, −10)?

dezoksy [38]

Answer:

15

Step-by-step explanation:

gradient=(change in Y coordinate/change in X coordinate)

=y1-y2/X1-X2

6 0

3 years ago

Read 2 more answers

When fritz drives to work his trip takes 40 minutes, but when he takes the train it takes 30 minutes. find the distance fritz t

sweet-ann [11.9K]

Distance = rate*time

convert minutes to hour first because the question talking about 15 mile per hour
40 mins = 40/60 2/3 hrs
30 mins = 30/60 = 1/2hrs

Assume that s be the speed when Fritz driving, so
s + 15 will be the speed of the train.

We know the time we know the speed, Next
distance that Fritz drive = $\frac{2}{3}s$
distance the train travel = $\frac{1}{2}(s+15)$

The question: Assume that the train travels the same distance as the car
==> $\frac{2}{3}s = \frac{1}{2}(s+15)$
==> $\frac{2}{3}s = \frac{1}{2}s + \frac{15}{2}$
==> $\frac{2}{3}s - \frac{1}{2}s = \frac{15}{2}$
==> $\frac{1}{6}s = \frac{15}{2}$
==> $\frac{6}{1} * \frac{1}{6}s = \frac{15}{2} * \frac{6}{1}$
==> $s = 45$
Now we know that Fritz drive at 45 mph,
distance = $\frac{2}{3} * 45 = 30 miles$

3 0

3 years ago