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7nadin3 [17]
3 years ago
5

PLEASE ASAP FOR FULL POINTS

Mathematics
1 answer:
NARA [144]3 years ago
3 0
It’s between B or C
Sorry if I’m wrong
You might be interested in
1) x+30 = 40
soldier1979 [14.2K]

1)x+30=40

x=40-30

Answer :x=10

2)30-20+2x=10

10+2x=10

2x=0

Answer: x=0

3)3x-10+13=-2x+28

3x+3=-2x+28

3x+2x+3=28

3x+2x=28-3

5x=28-3

5x=25

x=5

4)13x-23-45=-7x+12

13x-68=-7x+12

13x+7x-68=12

13x+7x=12+68

20x=12+68

20x=80

x=4

5)2(x+4)=10x+24

2x+8=10x+24

2x-10x+8=24

2x-10x=24-8

-8x=24-8

-8x=16

x=-2

6)3(x-5)=1-(2x-4)

3x-15=1-(2x-4)

3x-15=1-2x+4

3x-15=5-2x

3x+2x-15=5

3x+2x=5+15

5x=5+15

5x=20

x=4

7)5x-10=15

5x=15+10

5x=25

x=5

8)x+4=x+6

4=6

no solution

PLEASE MARK ME AS BRAINLIEST

4 0
3 years ago
The population of a city (in millions) at time t (in years) is P(t)=2.6 e 0.005t , where t=0 is the year 2000. When will the pop
lora16 [44]

Answer:

  year 2139

Step-by-step explanation:

The population will double when the factor e^(.005t) is 2.

  e^(.005t) = 2

  .005t = ln(2)

  t = ln(2)/0.005 = 138.6

The population will be double its size at t=0 when t=138.6. That is the population will be about 5.2 million in the year 2139.

7 0
3 years ago
Can anyone help me? I’m stuck big time.
user100 [1]
The answer is 27 degrees I believe
4 0
3 years ago
What is 3.25 x $1.40
Korolek [52]

Answer:

if you make the 3.5 equal 7/2

and the 1.40 equal 7/5 its will be more easier

so7/5 × 7/2 its 4.9

sorry guys its not 4.9 i made mistake with 3.25 i was thinking that it was 3.50 any wwy

i have good method too

we can make 3.25 equal 13/4 and 1.40 equal 7/5 the multiply it

we will find 91/20 but we have problem its The 10 dont worry we can take the 10 from the both number and we will get 9.1/2 and We can devide easily now and the answer is 4.55

sorry iam trying so hard to speak engilish well sorry if u cannot understand me big respet for all the students

8 0
3 years ago
Read 2 more answers
Differentiate with respect to x : 2xe^x​
Gnom [1K]

\\ \sf\longmapsto \dfrac{d}{dx}2xe^x

  • Apply product rule

\\ \sf\longmapsto \dfrac{d}{dx}2x(e^x)

\\ \sf\longmapsto 2x\dfrac{d}{dx}e^x+e^x\dfrac{d}{dx}2x

\\ \sf\longmapsto 2xe^x+2e^x

\\ \sf\longmapsto 2e^x(x+1)

7 0
2 years ago
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