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3 years ago

What is the limit as x approaches negative infinity of (1.001)^x ...?

1 answer:

3 0

<span>To answer this question we need to know that because x will always be negative, it is the same as saying lim as x approaches infinity of 1/(1.001)^x. That is why we can say that the denominator will get bigger and bigger, making the fraction and therefore the limit closer and closer to 0. </span>

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Here is a linear equation: y = 10+ 1. Are (1,1.5) and (12, 4) solutions to the equation? Select the correct choice.

Yuki888 [10]

Answer:

[see below]

Step-by-step explanation:

Assuming that the equation is y = 10x + 1

(12, 4)

4 = 10(12) + 1

4 = 120 + 1

4 ≠ 121

(12, 4) is not a solution.

(1, 1.5)

1.5 = 10(1) + 1

1.5 = 10 + 1

1.5 ≠ 1

They are not solutions to the equation.

Hope this helps.

7 0

2 years ago

What 4.2 times 0.7 /a is 294 /b is 2.94 /c 29.4

zvonat [6]

Answer:

29.4

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Toru takes his dog to be groomed. The fee to groom the dog is $75 plus 7% tax. Is $80 enough to pay for the service? Explain.

weqwewe [10]

80$ won't be enough to pay
He would like need 6 more cents
he needs 80.06$
because

7 0

2 years ago

Find the amount of each payment to be made into a sinking fund which earns 9% compounded quarterly and produces $43 comma 000

Solnce55 [7]

Answer:

$2647.18

Step-by-step explanation:

Formula : $A[\frac{1+(\frac{r}{n})^{n}-1 }{(\frac{r}{n} )}]$

Future value = $43,000

r = rate of interest = 9% = 0.09

t = 3.5 years (compounded quarterly)

n = number of compounding (3.5 × 4) = 14

Now put the values into formula :

43000 = $A[\frac{1+(\frac{0.09}{4})^{14}-1 }{(\frac{0.09}{4} )}]$

$43000=A(\frac{(1+0.0225)^{14}-1}{\frac{0.09}{4}})$

$43000=A(\frac{(1.0225)^{14}-1}{0.0225})$

43000=A( $\frac{0.365483427}{0.0225})$

43,000 = A(16.243708)

A = $\frac{43000}{16.243708}$

A = $2,647.17883 ≈ $2647.18

5 0

3 years ago

Two balls A and B rotate along a circular track. Ball A makes 4 full rotations in 120 seconds. Ball B makes 3 full rotation in 6

lara [203]

Find the rate in which both balls make one full rotation around the track.

Ball A:

$120 / 4 = 30$

It takes 30 seconds for Ball A to make a full rotation.

Ball B:

$60 / 3 = 20$

It takes 20 seconds for Ball B to make a full rotation.

Find the least common multiple of 20 and 30 to find the time at which they'll meet.

Multiples of 20: {20,40,60}
Multiples of 30: {30,60}

60 is the least common multiple of both 20 and 30.

The balls will meet again at 60 seconds.

5 0

3 years ago