Its factors would be
(x+2)*(x-1)*(x+0)
x^2 +x -2
x^3 + 0 + x^2 + 0 -2x +0
Equation: x^3 + x^2 -2x
f(2) = 8 + 4 -4
2x^3 + 2x^2 -4x +0
f(2) = 16 + 8 -8
3x^3 + 3x^2 -6x +0
f(2) = 24 +12 -12
4x^3 + 4x^2 -8x +0
f(2) = 32 +16 -16
So, the equation is:
4x^3 + 4x^2 -8x = 0
<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em><em>.</em>
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That's impossible to say. The radius of a square is meaningless.
Answer:
4ab² + 20b - 3a
Step-by-step explanation:
This question most likely asks us to simplify the expression, as factoring is not possible...
(ab² + 13b - 4a) + (3ab² + a + 7b),
ab² + 13b - 4a + 3ab² + a + 7b,
ab² + 3ab² + 13b + 7b - 4a + a,
Solution : 4ab² + 20b - 3a
