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never [62]
4 years ago
6

elsa recorded the different types of ice cream her friends like in the table below: ice cream type number of friends chocolate 3

pistachio 1 strawberry 2 vanilla 4 which of the following plots represents the data in the table?
Mathematics
2 answers:
Papessa [141]4 years ago
8 0
The question is asking to states the plot the could represent the data in the table, and base on my further research and understanding the table, the answer would be <span>A dot plot line labeled Ice Cream and titled Ice Cream Flavors. Four tick marks labeled Chocolate, Pistachio, Strawberry, and Vanilla. I hope this would help </span>
Troyanec [42]4 years ago
5 0

It's actually C, if you read the graph you will see it

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.65 repeating as a fraction?
Margarita [4]
Hey there 

.65 as a decimal would be <span>13/20
13 divided by 20 = 0.65
0.65 is also know as .65

hope this helps 

</span>
5 0
3 years ago
Evan has $4,000 that he wants to put into a saving account until he leaves dor college, which will be 6 years from now. How much
Bezzdna [24]

Steps:
1) 4,000 * .045 = 180
2) 180 * 6 = 1,080
3) 4,000 + 1,080 = 5,080

4)4,000 * .049 = 196
5) 196 * 6 = 1,176
6) 4,000 + 1,176 = 5,176
7) 5,176 - 5,080 = $96
Answer= $96
8 0
3 years ago
Six cards numbered from 1 to 6 are placed in an empty bowl. First one card is drawn and then put back into the bowl; then a seco
kari74 [83]

Answer:

C. \frac{1}{18}

Step-by-step explanation:

Given: Six cards numbered from 1 to 6 are placed in an empty bowl. First one card is drawn and then put back into the bowl then a second card is drawn.

To Find: If the cards are drawn at random and if the sum of the numbers on the cards is 8, what is the probability that one of the two cards drawn is numbered 5.

Solution:

Sample space for sum of cards when two cards are drawn at random is \{(1,1),(1,2),(1,3)......(6,6)\}

total number of possible cases =36

Sample space when sum of cards is 8 is \{(3,5),(5,3),(6,2),(2,6),(4,4)\}

Total number of possible cases =5

Sample space when one of the cards is 5 is \{(5,3),(3,5)\}

Total number of possible cases =2

Let A be the event that sum of cards is 8

p(\text{A}) =\frac{\text{total cases when sum of cards is 8}}{\text{all possible cases}}

p(\text{A})=\frac{5}{36}

Let B be the event when one of the two cards is 5

probability than one of two cards is 5 when sum of cards is 8

p(\frac{\text{B}}{\text{A}})=\frac{\text{total case when one of the number is 5}}{\text{total case when sum is 8}}

p(\frac{\text{B}}{\text{A}})=\frac{2}{5}

Now,

probability that sum of cards 8 is and one of cards is 5

p(\text{A and B}=p(\text{A})\times p(\frac{\text{B}}{\text{A}})

p(\text{A and B})=\frac{5}{36}\times\frac{2}{5}

p(\text{A and B})=\frac{1}{18}

if sum of cards is 8 then probability that one of the cards is 8 is \frac{1}{18}, option C is correct.

3 0
3 years ago
6 more than 5 times a number y
natta225 [31]
6+5y is the equation
7 0
3 years ago
Read 2 more answers
What division problem equals 184.32
Wewaii [24]

Answer:

There are many answers applicable to this question, one of them is 368.64/2 = 184.32

Step-by-step explanation:

All you have to do is multiply 184.32 times two. You can also try this with other numbers.

8 0
3 years ago
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