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3 years ago

I need help on #5 please!

Mathematics

1 answer:

Alex Ar [27]3 years ago

6 0

2x^2 + 2y^2 + 2xy I think

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WORTH 50!! Answer it with explanation and the answer is not y+6 I have some idea on how to do this.

mafiozo [28]

Answer:

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line $2x-3y=12$ is $3x+2y=34$

Step-by-step explanation:

Given:

$2x-3y=12$

To Find:

Equation of line passing through ( 16, -7) and is perpendicular to the line

$2x-3y=12$

Solution:

$2x-3y=12$ ...........Given

$\therefore y=\dfrac{2}{3}\times x-4$

Comparing with,

$y=mx$

Where m =slope

We get

$Slope = m1 = \dfrac{2}{3}$

We know that for Perpendicular lines have product slopes = -1.

$m1\times m2=-1$

Substituting m1 we get m2 as

$m2=-\dfrac{3}{2}$

Therefore the slope of the required line passing through (16 , -7) will have the slope,

$m2=-\dfrac{3}{2}$

Now the equation of line in slope point form given by

$(y-y_{1})=m(x-x_{1})$

Substituting the point (16 , -7) and slope m2 we will get the required equation of the line,

$(y-7)=-\dfrac{3}{2}\times (x-16)\\\\2y+14=-3x+48\\3x+2y=34......Equation\ of\ line$

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line $2x-3y=12$ is $3x+2y=34$

6 0

3 years ago

Please help me pleaseee

kaheart [24]

162 / 2 = 81
the answer is D

4 0

3 years ago

The graph of a polynomial S(x) = (2x - 3)(x – 4)(x+3) has x-intercepts at 3.x values.

dezoksy [38]

Answer:

Step-by-step explanation:

x-intercepts exist where y is equal to 0. Where y is equal to 0 is where the graph goes through the x-axis. Our x-intercepts are (2x-3), (x + 3), and (x-4). Again, since x-intercepts exist where y = 0, then by the Zero Product Property, 2x - 3 = 0, x - 4 = 0, and x + 3 = 0. In the first x-intercept:

2x - 3 = 0 and

2x = 3 so

x = 3/2

In the second:

x - 4 = 0 so

x = 4

In the third:

x + 3 = 0 so

x = -3

So the x-intercepts in the correct order are x = 3/2, 4, -3

6 0

3 years ago

What is the answer? Reduce 981/387

Sergeu [11.5K]

$\frac{981}{387}\\\\981\to9+8+1=18-is\ divisible\ by\ 9\\\\387\to3+8+7=18-is\ divisible\ by\ 9\\\\\frac{981:9}{387:9}=\frac{109}{43}\\\\109\ and\ 43\ are\ the\ prime\ numbers\\\\Answer:\boxed{\frac{981}{387}=\frac{109}{43}=2\frac{23}{43}}$

7 0

3 years ago

Read 2 more answers

Exponential growth or exponential decay last question please help ?

maksim [4K]

This is exponential growth because the peak starts at the negative side and it ends up at the positive side. Therefore, it is exponential growth.

6 0

3 years ago