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denis23 [38]
3 years ago
11

Please help me asap!!

Mathematics
2 answers:
lara31 [8.8K]3 years ago
5 0
35
Jdmd I eu to the form that
Alika [10]3 years ago
3 0

Answer:

35

Step-by-step explanation:

what I did was add GJ together and imaged it in my head to see if it would fit... I'm not sure tho

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Helphelphelphelphelphelphelp
adoni [48]

Answer:

P = 1,-10

Q=1,-1

R=7,-1

S=7,-10

6 0
3 years ago
Here are the last 3 can u help me
alexandr1967 [171]

Answer:

13. B

14. non-proportional

15. y = 4x+35

7 0
3 years ago
HELP!!!! I think its C but I'm not sure!
MA_775_DIABLO [31]

Answer:

The fundamental theorem of algebra tells you that the equation will have two complex roots since the degree of the polynomial is 2. The roots are x=1\pm i\sqrt{7}.

Step-by-step explanation:

Consider the provided information.

Algebra's fundamental theorem states that: Every polynomial equation of degree n with complex coefficients has n roots in the complex numbers.

Now consider the provided equation.

2x^2-4x+16=0

The degree of the polynomial equation is 2, therefore according to Algebra's fundamental theorem the equation have two complex roots.

Now find the root of the equation.

For the quadratic equation of the form ax^2+bx+c=0 the solutions are: x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Substitute a=2,\:b=-4,\:\ and \ c=16 in above formula.

x_{1,\:2}=\frac{-\left(-4\right)\pm \sqrt{\left(-4\right)^2-4\cdot \:2\cdot \:16}}{2\cdot \:2}

x_{1,\:2}=\frac{4\pm \sqrt{16-128}}{4}

x_{1,\:2}=\frac{4\pm \sqrt{-112}}{4}

x_{1,\:2}=\frac{4\pm 4i\sqrt{7}}{4}

x_{1,\:2}=1\pm i\sqrt{7}

Hence, the fundamental theorem of algebra tells you that the equation will have two complex roots since the degree of the polynomial is 2. The roots are x=1\pm i\sqrt{7}.

4 0
3 years ago
Which relation is a function?
lora16 [44]

Answer:

Choice A.

Step-by-step explanation:

Every other choice has multiple of the same x-values that have different corresponding y-values.

3 0
3 years ago
Is this a quadrilateral?
Pepsi [2]
A quadrilateral is a 4-sided figure. so yes, i'd say that is a quadrilateral
4 0
3 years ago
Read 2 more answers
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