Write an equation for the function that includes the points (-2,3) and (-1,9)
2 answers:
Answer:
f(x)=6x+15
Step-by-step explanation:
first you find the gradient of the equation with the gradient formula by using the two given points
the gradient is 6, so using the slope equation which is y=mx+b sub 6 into the gradient
you then get y=6x+b
to find b just sub in any of the points and solve the equation.
ps. f(x) essentially stands for a y so don't get confused
hope this helps :)
Answer:
y = 6x + 15.
Step-by-step explanation:
The slope of the line joining these 2 points =
(9-3)/(-1-(-2))
= 6/1
= 6
Use the point-slope form of a straight line:
y - y1 =m(x - x1) Here m = 6 and (x1, y1) will be (-2, 3), so:
y - 3 = 6(x -(-2))
y - 3 = 6(x + 2)
y = 6x + 12 + 3
y = 6x + 15.
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Answer:
x = 50
m∠D = 150°
m∠F = 30°
Step-by-step explanation:
- supplementary angles are two angles whose sum is 180°
∠D + ∠F = 180°
3x + x - 20 = 180
3x + x = 180 + 20
4x = 200
x = 200/4
x = 50
D = 3*50 = 150
∠D = 150°
F = 50 - 20 = 30
∠F = 30°
Hello,
![-20 \leq 3x+1 \leq 10\\ \Rightarrow\ -21 \leq 3x \leq 9\\ \Rightarrow\ -7 \leq x \leq 3\\ Sol=[-7\ 3]\ if\ x\ is\ a\ real. ](https://tex.z-dn.net/?f=-20%20%5Cleq%203x%2B1%20%5Cleq%2010%5C%5C%0A%5CRightarrow%5C%20-21%20%5Cleq%203x%20%5Cleq%209%5C%5C%0A%5CRightarrow%5C%20-7%20%5Cleq%20x%20%5Cleq%203%5C%5C%0A%0ASol%3D%5B-7%5C%203%5D%5C%20if%5C%20x%5C%20is%5C%20a%5C%20real.%0A)
Answer:
<em>9.</em>
Step-by-step explanation:
3 * √)0^2 + 3^2)
= 3*3
= 9.
Answer:
x=0/y=-2
y=0/x=-3
....∞
Step-by-step explanation:
Three days
1 1/4 = 5/4
1/2= 2/4
2/4+1/4= 3/4 the first day
5/4-3/4= 2/4
2/4 = 1/4 and 1/4 = two days
the first day+ two days= 3 days
