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3 years ago

Dejuan raked leaves for 42 minutes. what fraction of an hour did he rake leaves in simplest form

Mathematics

2 answers:

stiv31 [10]3 years ago

8 0

42/60 ---> 7/10=0.7 hope this helps :)

Effectus [21]3 years ago

5 0

You could do 42/60 but also simplify it down to 7/10

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3 years ago

What is 11inches redistributed equally among the 12 months

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3 years ago

Which of the following can be used to calculate the volume of water inside the fish bowl?

Lunna [17]

The volume of a sphere can be calculated as

$V=\frac{4}{3}\pi r^3$

Where r is the radius of the sphere

We want to calculate half of the volume, then we must divide that volume by 2

$V^{\prime}=\frac{1}{2}\frac{4}{3}\pi r^3$

Now we must find the radius of our sphere, the segment AB is the diameter of the sphere, and the radius is half od the diameter, then

$r=\frac{AB}{2}=\frac{12}{2}=6$

Let's put it into our equation

$\begin{gathered} V^{\prime}=\frac{1}{2}\left(\frac{4}{3}\right)(\pi)(r)^3 \\ \\ V^{\prime}=\frac{1}{2}\left(\frac{4}{3}\right)(\pi)(6)^3 \end{gathered}$

The problem says to use

$\pi\approx\frac{22}{7}$

Then

$V^{\prime}=\frac{1}{2}\left(\frac{4}{3}\right)\left(\frac{22}{7}\right)(6)^3$

Final answer:

The formula that can be used to calculate the volume of water inside the fish bowl is

$V=\frac{1}{2}\left(\frac{4}{3}\right)\left(\frac{22}{7}\right)(6)^3$

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1 year ago

What is the area of a rectangle with vertices at (4, 3), (11, 3), (11, 9), and (4, 9)?

Brums [2.3K]

Answer:

The area of a rectangle is 42 units ².

Step-by-step explanation:

As the diagram is given below.

Distance Formula

$Distance\ formula = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

As the rectangle with vertices at A (4, 3), B(11, 3),C (11, 9), and D (4, 9).

Take A (4, 3) to B(11, 3)

$AB = \sqrt{(11-4)^{2}+(3-3)^{2}}$

$AB = \sqrt{(7)^{2}+(0)^{2}}$

$AB = \sqrt{49}$

$\sqrt{49} =7$

AB = 7 units

As take B(11, 3) to C (11, 9).

$BC = \sqrt{(11-11)^{2}+(9-3)^{2}}$

$BC = \sqrt{(0)^{2}+(6)^{2}}$

$BC = \sqrt{36}$

$\sqrt{36} =6$

BC = 6 units

As take C (11, 9) toD (4, 9).

$CD = \sqrt{(4-11)^{2}+(9- 9)^{2}}$

$CD = \sqrt{(7)^{2}+(0)^{2}}$

$CD = \sqrt{49}$

$\sqrt{49} =7$

CD = 7 units

As take D (4, 9) to A (4, 3)

$DA = \sqrt{(4-4)^{2}+(3-9)^{2}}$

$DA = \sqrt{(0)^{2}+(-6)^{2}}$

$DA = \sqrt{36}$

$\sqrt{36} =6$

DA = 6 units

Thus

AB = DC= 7 units

AD = BC = 6 units

Formula

Area of rectangle = Length × Breadth

Length = 7 units

Breadth = 6 units

Put value in the above

Area of rectangle = 7 × 6

= 42 units ²

Therefore the area of a rectangle is 42 units ².

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3 years ago

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