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4 years ago

12

Find an exact value. Cosine of negative seven pi divided by twelve

2 answers:

Dmitrij [34]4 years ago

6 0

<span><span>−<span><span>7/12</span><span></span></span>+(cosı)ne

I hope this helps. :)
</span><span>
</span></span>

valkas [14]4 years ago

3 0

Well π=180°
-7π/12=x
x=-7π*180°/12
=105°

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Adam had dimes and quarters in his pocket there are 28 coins in all and they are worth of $4.68 altogether how many quarters doe

Paraphin [41]

Use a system to find the answer. x is quarters and y is dimes
x +y = 28 and 0.25x + 0.1y =4.68 The point where they intersect is the answer. However there is no real number solution to this because coins cannot be split. This would make sense because you would need pennies to get 68 cents.

4 0

3 years ago

Burka [1]

Answer:

D. (–2, –2); minimum

Step-by-step explanation:

It’s D you got to see the lowest part of the graph and you will call it mini except if the graph was going down you will call that point maximum.

Answer:

D. (-2, -2); minimum

Step-by-step explanation:

The vertex is the where the curve turns up/down which divides the figure into two halves.

From the given graph, the graph turns up at (-2, -2) , the graph moves down, therefore, the vertex (-2, -2); minimum.

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3 years ago

Hector bought 6 bags of candy. There were 7 pieces of candy in each bag. How many pieces of candy did Hector buy?

Troyanec [42]

Answer:

42 pieces (6*7)

Step-by-step explanation:

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3 years ago

Read 2 more answers

Which expression is equivalent to RootIndex 3 StartRoot StartFraction 75 a Superscript 7 Baseline b Superscript 4 Baseline Over

slega [8]

Answer:

B. $\frac{b}{2a^{2}c^3}\sqrt[3]{15b}$

Step-by-step explanation:

Given:

The expression to simplify is given as:

$\sqrt[3]{\frac{75a^7b^4}{40a^{13}c^9}}$

Use the exponent property $\frac{a^m}{a^n}=a^{m-n}$

$\frac{a^7}{a^{13}}=a^{7-13}=a^{-6}$

Use the exponent property $(a^m)^n=a^{m\times n}$

$a^{-6}=a^{-2\times 3}=(a^{-2})^3$

$b^4=b\times b^3\\c^{9}=(c^3)^3$

Reducing $\frac{75}{40}$ to simplest form, we get:

$\frac{5\times 5\times 3}{2^3\times 5}=\frac{15}{2^3}$

Therefore, expression becomes:

$\sqrt[3]{\frac{15(a^{-2})^3\times b\times b^3}{2^3(c^3)^3}}$

Use the cubic root property:

$\sqrt[3]{x^3} =x$ . Thus, the expression becomes:

$\frac{a^{-2}b}{2c^3}\sqrt[3]{15b}$

Using the exponent property $a^{-m}=\frac{1}{a^m}$

$a^{-2}=\frac{1}{a^2}$

So, the final expression is:

$\frac{b}{2a^{2}c^3}\sqrt[3]{15b}$

Therefore, the correct option is option B.

7 0

4 years ago

Convert the percent to a decimal<br> 24 1/2%

Ann [662]

Answer:

0.245

Step-by-step explanation:

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=0.245

8 0

3 years ago