Answer:
Total money they had at first $252.
Step-by-step explanation:
Let,
x be the amount Silas had originally
y be the amount Raja had originally
According to given statement;
x = 3y Eqn 1
x - 84 = y + 42 Eqn 2
Putting x=3y in Eqn 2
3y - 84 = y + 42
3y - y = 42 + 84
2y = 126
Dividing both sides by 2
Putting y = 63 in Eqn 1
x = 3(63)
x = 189
Total money they originally had = 189 + 63 = $252
Hence,
Total money they had at first $252.
Answer:
slope1 : 7, slope 2 = 3 solution: (2,5)
Step-by-step explanation:
I simplify some steps
pair 1: x1 0 2
y1 -9 5 ........ -9, y1 intercept
pair 2: x2 0 2
y2 -1 5 ........ -1, y2 interept
2 pairs meet at (2,5)
y=7x-9 ......A
y=3x-1 ......B
A-B 0=4x-8
4x=8
x=2
y=5
slope 1=( y2-y1) / (x2-x1) = (5- -9)/(2-0) = 14/2 =7
slope 2 = (5 - -1) / (2 - 0) = 6/2 = 3
It would still be 17.8, unless there are more numbers after the 8.
Answer:
(3,2) I think
Step-by-step explanation:
X= 3
Y=2
3 +2 =5
3-2=1
I think the mode is 9.875
