Let
be the random variable for the number of marks a given student receives on the exam.
10% of students obtain more than 75 marks, so

where
follows a standard normal distribution. The critical value for an upper-tail probability of 10% is

where
denotes the CDF of
, and
denotes the inverse CDF. We have

Similarly, because 20% of students obtain less than 40 marks, we have

so that

Then
are such that


and we find

Hello here is a solution :
Remember, ab+ac=a(b+c)
undistribute the 14
14(l)+14(3a)=14(l+3a)
D is answer
Answer:
9m3
Step-by-step explanation:
multiply every thing if the answer is not satisfactory its because there is a bunch of info losing
Answer:
-12
Step-by-step explanation:
6 + 1.5x = -12
1.5x = -18
x = -12