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pishuonlain [190]
2 years ago
10

William put $100 in a bank account last year. Now he has more money in the account. Which expressions represent how much money W

illiam has in his bank account now? Choose all answers that are correct.
A. $100 - (1/12 * $100)

B. $100 + (1/12 * $100)

C. $100 + (13/12 * $100)

D. 13/12 * $100


I think B. and D. are correct because they are both equal. Could someone help me understand this, and tell if I'm right or wrong? Thanks! <3
Mathematics
2 answers:
Harman [31]2 years ago
7 0
Its b an its wright Oh no! Something went wrong while adding your answer<span><span>It's too short. Write at least 20 characters to explain it well.</span><span>
</span></span>
gulaghasi [49]2 years ago
5 0
You are right the answers are B and D because in both we have 100$ at the first :))
i hope this is helpful
have a nice day 
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The girls soccer team won 10 games and the lost 2. And the boys soccer team won 12 games and lost 3. What is the ratio of the gi
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Read 2 more answers
I GIVE BRAINLIEST PLS HELP
ioda
The answer is 8
Here's why:
{ ( \frac{( {6}^{7}) \times ( {3}^{3})  }{(  {6}^{6}) \times ( {3}^{4}  ) } )}^{3}  =   \\ ( \frac{6}{3} ) ^{3}  =  \\ \frac{216}{27}  = 8
The exponents are subtracted one from another when divided.
\frac{ a ^{b} }{ {a}^{c} } =  {a}^{b - c}
We can look at the problem this way:
( \frac{6^{7} }{6 ^{6} }  \times  \frac{3^{3} }{ {3}^{4} } ) = (6^{7 - 6}  \times  {3}^{3 - 4} ) =  \\ ({6}^{1}  \times  {3}^{ - 1} )
Since we have the power of -1 on the 3, we apply this rule:
{a}^{ - b}  =  \frac{1}{ {a}^{b} }
Also this rule because we have the power of 1 on the 6:
{a}^{1}  = a
Then we get this:
(6 \times  \frac{1}{3} )^{3}  = ( \frac{6}{3} )^{3}
We apply the rule:
( \frac{a}{b}) ^{c}   =  \frac{ {a}^{c} }{ {b}^{c} }
We get this:
\frac{{6}^{3} }{ {3}^{3} } =  \frac{216}{27}  = 8
4 0
3 years ago
Please find mA and mB please.
Nikitich [7]
The ANSWERRRRRRR would be 32
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c) 8,000,000 + 100,000 + 5

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