Mr. and Mrs.Garcia took their three children to see a matinée on saturday.They spent a total of $55.50,which included $29.25 at
2 answers:
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(a) Length of the height is 2.732 m
(b) Length of the base is 5.466 m
<u>Explanation:</u>
An image is attached for reference.
(a)
In ΔAOB,
In ΔBGD,
According to the figure, BG = OE = 1.732 m
Height of the tent, AE = AO + OE
= 1 m + 1.732 m
= 2.732 m
(b)
DF = ?
In ΔAOB,
According to the figure, OB = GE = 1.733 m
In ΔBGD,
According to the figure, DE = DG + GE
DE = 1 m + 1.733 m
DE = 2.733 m
Length of the base, DF = 2 X DE
DF = 2 X 2.733 m
DF = 5.466 m
This is just a shape with a peace of it cut out so if we imagine how would this figure be before it was cut. it would give us an 4×12×6 cuboid (we can use that) so first, lets caculate the volume of the bigger cuboid
then we need to caculate the valume of the two smaller cuboids.
by subtracting the valume of the bigger cuboid from our two smaller ones we will have the valume of the three-dimensional figure.
65+96=160
288-160=128
then we need to caculate the valume of the two smaller cuboids.
by subtracting the valume of the bigger cuboid from our two smaller ones we will have the valume of the three-dimensional figure.
65+96=160
288-160=128