(From top to bottom) wrong, right, right, right, wrong. This is because a irrational*an irrational number is rational, but a rational*an irrational is an irrational number
Answer:
If y(x-y)^2=x, then int1/(x-3y)dx is equal to (A) 1/3log{(x-y)^2+1} (B) 1/4log{(x-y)^2-1} (C) 1/2log{(x-y)^2-1} (D) 1/6 log{(x^2-y^2-1}
Step-by-step explanation:
The answer is that y is equal to -3 and x is equal to 7
2x-y=17
-2(x-y)=10 )
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2x-y=17
-2x+2y=-20
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y=-3
x-y=10
x-(-3)=10
x+3=10
-3 -3
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x=7
24 """"""""""""""""""""""""
I only got 22-25 done cause its been a long time since ive done these so i don't remember how to do the first two ):
