Question

"The main program will call a series of methods to process a set of data. One method will read data into an array. A second method will print the values stored in an array in a neat format. Another method will find the average of the values stored in an array. A fourth method will construct a new array from an existing array."

Answer 1

Answer:

Check the explanation

Explanation:

import java.util.*;

import java.io.File;

public class Main

{

 

public static void main(String[] args) {

           

double[] second = new double[10];

double[] arr = new double[10];

arr = readData(10,arr);

     

System.out.println("here is the original array");

     

printArray(3,arr);

double avg = findAverage(5,arr);

System.out.println("The avearage value is" + avg);

System.out.println("here is the new array");

     

second = howFarAway(9,avg,arr,second);

     

printArray(3,narr);

     

avg = findAverage(5,narr);

System.out.println("The avearage value is" + avg);

 

}

public static double[] readData(int n,double[] numbers)

  {

 

      File file = new File("number.txt");

Scanner fileScanner = new Scanner(file);

      for(int i=0; i<n; i++)

          numbers[i]=fileScanner.nextDouble();

 

  return numbers;

 

  }

 

public static void printArray(int q, double[] numb)

 

  {

 

      for(int i=0;i<numb.length;i++)

 

      {

 

          System.out.print(numb[i]);

          System.out.print(" ");

 

          if((i+1)%q==0)

              System.out.println("");

 

      }

  }

 

public static double findAverage(int k ,double[] p)

 

  {

  double s=0;

 

  for(int i=0;i<k;i++)

  s = s+p[i];

 

  return s/k;

 

  }

public static double[] howFarAway(int m,double avg,double[] arr,double[] narr)

 

  {

 

      for(int i=0;i<arr.length;i++)

  narr[i]=arr[i]-avg;

 

      return narr;

 

  }

}