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dangina [55]
3 years ago
14

A network that typically reaches a few meters, such as up to 10 meters (33 feet), and consists of personal devices such as mobil

e computers, smartphones, and handheld devices is called:_______
Computers and Technology
1 answer:
Salsk061 [2.6K]3 years ago
7 0

Answer:

<em>PAN (Personal Area Network)</em>

Explanation:

A network that typically reaches only a few meters (10 m or 33 ft) and contains personal devices like mobile computers, smartphones and handheld devices is called <em>PAN (Personal Area Network).</em>

<em></em>

PAN enables communication between devices that are near a human being (i.e. only for shorter distances).

It can be wireless such as bluetooth earphones used with the smartphone, wireless keyboard and mouse used with laptop or computer, TV and remote control communication.

It can be wired such as wired earphones used with the smartphone, any USB (Universal Serial Bus) device connected to a computer/laptop.

You might be interested in
Crashing almost always accelerates the schedule while increasing project risk, whereas fast tracking almost always accelerates t
Ivahew [28]

Answer: False

Explanation: Because fast-tracking doesn’t involve additional resources, it’s usually best to start with this technique while Crashing requires careful planning to prevent “panic mode” among the project crews and to avoid acceleration claims.

4 0
3 years ago
Given the following adjacency matrix, what is the approximate rank vector after one iteration of the power iteration method (use
ValentinkaMS [17]

Note: The matrix referred to in the question is: M = \left[\begin{array}{ccc}1/2&1/3&0\\1/2&1/3&0\\0&1/3&1\end{array}\right]

Answer:

a) [5/18, 5/18, 4/9]'

Explanation:

The adjacency matrix is  M = \left[\begin{array}{ccc}1/2&1/3&0\\1/2&1/3&0\\0&1/3&1\end{array}\right]

To start the power iteration, let us start with an initial non zero approximation,

X_o = \left[\begin{array}{ccc}1\\1\\1\end{array}\right]

To get the rank vector for the first Iteration:

X_1 = MX_0

X_1 =  \left[\begin{array}{ccc}1/2&1/3&0\\1/2&1/3&0\\0&1/3&1\end{array}\right]\left[\begin{array}{ccc}1\\1\\1\end{array}\right] \\\\X_1 = \left[\begin{array}{ccc}5/6\\5/6\\4/3\end{array}\right]\\

Multiplying the above matrix by 1/3

X_1 = \left[\begin{array}{ccc}5/18\\5/18\\4/9\end{array}\right]

8 0
3 years ago
Design and implement a class dayType that implements the day of the week in a program. The class dayType should store the day, s
Afina-wow [57]

The code is implemented based on the given operations.

Explanation:

#include <iostream>

#include <string>

using namespace std;

class dayType

{ private:

 string day[7];

 string presentDay;

 int numofDays;

public:

 void setDay(string freshDay);

 void printDay() const;

 int showDay(int &day);

 int nextDay(int day);

 int prevDay(int day) const;

 int calcDay(int day, int numofDays);    

 dayType()

 {

  day[0] = "Sunday";

  day[1] = "Monday";

  day[2] = "Tuesday";

  day[3] = "Wednesday";

  day[4] = "Thursday";

  day[5] = "Friday";

  day[6] = "Saturday";

  presentDay = day[0];

  numofDays = 0;

 };

 ~dayType();

};

#endif

#include "dayType.h"

void dayType::setDay(string freshDay)

{

  presentDay = freshDay;

}

void dayType::printDay()

{

  cout << "Day chosen is " << presentDay << endl;

}

int dayType::showDay(int& day)

{

  return day;

}

int dayType::nextDay(int day)

{

day = day++;

if (day > 6)

 day = day % 7;

switch (day)

{

case 0: cout << "The successive day is Sunday";

 break;

case 1: cout << "The successive day is Monday";

 break;

case 2: cout << "The successive day is Tuesday";

 break;

case 3: cout << "The successive day is Wednesday";

 break;

case 4: cout << "The successive day is Thursday";

 break;

case 5: cout << "The successive day is Friday";

 break;

case 6: cout << "The successive day is Saturday";

 break;

}

cout << endl;

return day;

}

 

int dayType::prevDay(int day)

{

day = day--;

switch (day)

{

case -1: cout << "The before day is Saturday.";

 break;

case 0: cout << "The before day is Saturday.";

 break;

case 1: cout << "The before day is Saturday.";

 break;

case 2: cout << "The before day is Saturday.";

 break;

case 3: cout << "The before day is Saturday.";

 break;

case 4: cout << "The before day is Saturday.";

 break;

case 5: cout << "The before day is Saturday.";

 break;

default: cout << "The before day is Saturday.";

}

cout << endl;

return day;

}

int dayType::calcDay(int addDays, int numofDays)

{

addDay = addDays + numofDays;

if (addDay > 6)

 addDay = addDay % 7;

switch(addDay)

{

case 0: cout << "The processed day is Sunday.";

 break;

case 1: cout << "The processedday is Monday.";

 break;

case 2: cout << "The processedday is Tuesday.";

 break;

case 3: cout << "The processedday is Wednesday.";

 break;

case 4: cout << "The processedday is Thursday.";

 break;

case 5: cout << "The processedday is Friday.";

 break;

case 6: cout << "The processedday is Saturday.";

 break;

default: cout << "Not valid choice.";

}

cout << endl;

return addDays;

}

4 0
3 years ago
Given an list of N integers, Insertion Sort will, for each element in the list starting from the second element: Compare the ele
Elena L [17]

Answer:

def insSort(arr):

ct=0;

for i in range(1, len(arr)):

key = arr[i]

j = i-1

while j >=0 and key < arr[j] :

arr[j+1] = arr[j]

j -= 1

ct=ct+1;

arr[j+1] = key

return arr,ct;

print(insSort([2,1]))

Output of the program is also attached.

8 0
4 years ago
There are two String variables, s1 and s2, that have already been declared and initialized. Write some code that exchanges their
Ivan

Answer:

//here is code in java.

import java.util.*;

class Solution

{

// main method of class

public static void main (String[] args) throws java.lang.Exception

{

   try{

    // declare an initialize first string variables

     String st1="hello";

     // declare an initialize first string variables

     String st2="world";

     // create another string variable

    String st3;

    // exchange the value of both string variables

    st3=st1;

    st1=st2;

    st2=st3;

    System.out.println("value of first String after exchange: "+st1);

    System.out.println("value of second String after exchange: "+st2);

   }catch(Exception ex){

       return;}

}

}

Explanation:

declare and initialize two string variables.Create another string variable "st3". first assign value of "st1" to "st3" after then value of "st2" to "st1" and then  assign value of "st3" to "st2". This will exchange the values of both the string.

Output:

value of first String after exchange: world

value of second String after exchange: hello

8 0
3 years ago
Read 2 more answers
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