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lutik1710 [3]
3 years ago
5

Question 13 (1 point),

Mathematics
1 answer:
Firlakuza [10]3 years ago
7 0

13: Since f(1)=10, the sequence must start with 10. We have only one sequence starting with 10, and indeed it verifies f(n+1)=f(n)-2, i.e. the next term is 2 less than the previous one.

14: If y varies directly with x, then there is a constant of variation k such that

\dfrac{y}{x}=k \iff y=kx

In your case, F varies directly with m, with a constant of variation of 32.2, so we have

F=32.2m

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What is 0.0000091 written in scientific notation
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The goal of writing a number in scientific notation is to have a decimal number, with one digit to the left of the decimal point, followed by a <span>×⨯</span><span>1010</span> to some power. To format the number this way, multiply the <span>0.00000910.0000091</span> by <span>1010</span> <span><span>−6</span><span>-6</span></span> times, making it <span>9.19.1</span>. Each multiplication by <span>1010</span> moves the decimal point one digit to the left, but in order to keep the same number, multiply <span>9.19.1</span> by <span><span>10<span>−6</span></span><span>10<span>-6</span></span></span>.<span>9.1×<span>10<span>−<span>6</span></span></span></span>
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Read 2 more answers
Evacuate the following using suitable identities (102)^3
snow_lady [41]

The value of (102)^3 exists 1061208.

<h3>How to estimate the value of (102)^3?</h3>

Let us rewrite (102)^3 as (100+2)^3

Now utilizing the identity (a+b)^3=a^3+b^3+3ab(a+b), we get

a = 100 and b = 2 then substitute the values of a and b then

(100+2)^3=100^3+2^3+[(3\times100\times2)(100+2)]

= 1000000 + 8 + (600 × 102)

= 1000000 + 8 + 61200

= 1061208

Hence, (102)^3=1061208

Therefore, the value of (102)^3 exists 1061208.

To learn more about cubic polynomial equation refer to:

brainly.com/question/28181089

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2 years ago
How many zeros are in the product 50 * 7000 what is the answer​
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Answer:4

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5 0
3 years ago
Resistors are labeled 100 Ω. In fact, the actual resistances are uniformly distributed on the interval (95, 103). Find the mean
Zinaida [17]

Answer:

E[R] = 99 Ω

\sigma_R = 2.3094 Ω

P(98<R<102) = 0.5696

Step-by-step explanation:

The mean resistance is the average of edge values of interval.

Hence,

The mean resistance, E[R] = \frac{a+b}{2}  = \frac{95+103}{2} = \frac{198}{2} = 99 Ω

To find the standard deviation of resistance, we need to find variance first.

V(R) = \frac{(b-a)^2}{12} =\frac{(103-95)^2}{12} = 5.333

Hence,

The standard deviation of resistance, \sigma_R = \sqrt{V(R)} = \sqrt5.333 = 2.3094 Ω

To calculate the probability that resistance is between 98 Ω and 102 Ω, we need to find Normal Distributions.

z_1 = \frac{102-99}{2.3094} = 1.299

z_2 = \frac{98-99}{2.3094} = -0.433

From the Z-table, P(98<R<102) = 0.9032 - 0.3336 = 0.5696

5 0
4 years ago
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