Answer:
Following are the program in c language
#include<stdio.h> // header file
int main() // main function
{
int ar[10],k,biggest; // variable declaration
printf("Enter the ten values:\n");
for (k = 0;k < 10; k++)
{
scanf("%d", &ar[k]); // user input of 10 number
}
biggest = ar[0]; // store the array index of 0 into biggest variable
for (k = 0; k< 10; k++) // finding the biggest number
{
if (ar[k] >biggest)
{
biggest = ar[k];
}
}
printf(" biggest num is %d", biggest); // display the biggest number
return 0;
}
Output:
Enter the ten values:
12
2
4
5
123
45
67
453
89
789
biggest num is 789
Explanation:
Here we declared an array ar[10] of type int which store the 10 integer values.
Taking 10 integer input from the user in array ar .After that iterating the loop and finding the biggest number by using if statement and store the biggest number in biggest variable .
Finally display biggest number.
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Answer:
year = int(input("Enter a year: "))
if (year % 4) == 0:
if (year % 100) == 0:
if (year % 400) == 0:
print(str(year) + " - leap year")
else:
print(str(year) +" - not a leap year")
else:
print(str(year) + " - leap year")
else:
print(str(year) + "- not a leap year")
Explanation:
*The code is in Python.
Ask the user to enter a year
Check if the <u>year mod 4</u> is 0 or not. If it is not 0, then the year is not a leap year. If it is 0 and if the <u>year mod 100</u> is not 0, then the year is a leap year. If the <u>year mod 100</u> is 0, also check if the <u>year mod 400</u> is 0 or not. If it is 0, then the year is a leap year. Otherwise, the year is not a leap year.
