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Sphinxa [80]
1 year ago
6

By default word documents include _______ margins on all sides of the document.

Computers and Technology
1 answer:
torisob [31]1 year ago
4 0

Answer:

B

Explanation:

When you open a new Word Document, Microsoft automatically sets the Margins to 1 inch.

You might be interested in
Write a program that reads in an integer value for n and then sums the integers from n to 2 * n if n is nonnegative, or from 2 *
devlian [24]

Answer:

Following are the program in c++

First code when using for loop

#include<iostream> // header file  

using namespace std; // namespace

int main() // main method

{

int n, i, sum1 = 0; // variable declaration

cout<<"Enter the number: "; // taking the value of n  

cin>>n;

if(n > 0) // check if n is nonnegative

{

for(i=n; i<=(2*n); i++)

{

sum1+= i;

}

}

else //  check if n  is negative

{

for(i=(2*n); i<=n; i++)

{

sum1+= i;

}

}

cout<<"The sum is:"<<sum1;

return 0;

Output

Enter the number: 1

The sum is:3

second code when using while loop

#include<iostream> // header file  

using namespace std; // namespace

int main() // main method

{

int n, i, sum1 = 0; // variable declaration

cout<<"Enter the number: "; // taking the value of n  

cin>>n;

if(n > 0) // check if n is nonnegative

{

int i=n;  

while(i<=(2*n))

{

sum1+= i;

i++;

}

}

else //  check if n  is negative

{

int i=n;  

while(i<=(2*n))

{

sum1+= i;

i++;

}

}

cout<<"The sum is:"<<sum1;

return 0;

}

Output

Enter the number: 1

The sum is:3

Explanation:

Here we making 2 program by using different loops but using same logic

Taking a user input in "n" variable.

if n is nonnegative then we iterate the loops  n to 2 * n and storing the sum in "sum1" variable.

Otherwise iterate a loop  2 * n to n and storing the sum in "sum1" variable.  Finally display  sum1 variable .

4 0
3 years ago
Horizontal and vertical flips are often used to create ___.
mixer [17]

Answer:

Rotation of an image

Explanation:

The correct answer is -  Rotation of an image

Reason -

When you rotate an object, it moves left or right around an axis and keeps the same face toward you.

When you flip an object, the object turns over, either vertically or horizontally, so that the object is now a mirror image.

5 0
3 years ago
Suppose for the worst case, given input size n: Algorithm 1 performs f(n) = n2 + n/2 steps Algorithm 2 performs f(n) = 12n + 500
melomori [17]

Answer:

29

Explanation:

for n=28:

--------------

Algorithm 1 performs f(n) = n2 + n/2 = 28*28 + 28/2 = 798

Algorithm 2 performs f(n) = 12*28 + 500 = 836

for n=29

--------------

Algorithm 1 performs f(n) = n2 + n/2 = 29*29 + 29/2 = 855.5

Algorithm 2 performs f(n) = 12*29 + 500 = 848

so, for n=29, algorithm 2 will be faster than algorithm 1

6 0
3 years ago
Functions are ideal for use in menu-driven programs. When a user selects a menu item, the program can_______ the appropriate
Masteriza [31]

Answer:

a. call

Explanation:

According to my research on function, I can say that based on the information provided within the question the program can call the appropriate function. A function is a piece of code that completes a single task when called upon. Calling is another way of just saying that your telling the function to run its code at that given moment.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

4 0
3 years ago
create your own min function that finds the minimum element in a list and use it in a separate function
schepotkina [342]

Answer:

def minfunction(mylist):

   min = mylist[0]

   for i in mylist:

       if i < min:

           min = i

   print("The minimum is: "+str(min))

   

def anotherfunction():

   mylist = []

   n = int(input("Length of list: "))

   for i in range(n):

       listelement = int(input(": "))

       mylist.append(listelement)

   minfunction(mylist)

   

anotherfunction()

Explanation:

This solution is implemented in Python

This defines the min function

def minfunction(mylist):

This initializes the minimum element to the first index element

   min = mylist[0]

This iterates through the list

   for i in mylist:

This checks for the minimum

       if i < min:

... and assigns the minimum to variable min

           min = i

This prints the minimum element

   print("The minimum is: "+str(min))

   

This defines a separate function. This  separate function is used to input items into the list

def anotherfunction():

This defines an empty list

   mylist = []

This prompts user for length of list

   n = int(input("Length of list: "))

The following iteration inputs elements into the list

<em>    for i in range(n):</em>

<em>        listelement = int(input(": "))</em>

<em>        mylist.append(listelement)</em>

This calls the minimum function

   minfunction(mylist)

   

The main starts here and this calls the separate function

anotherfunction()

5 0
3 years ago
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