Answer:
1370
Step-by-step explanation:
<h3>Given</h3>
- AP with d= 7 and a₂₂ = 149
<h3>To find</h3>
<h3>Solution</h3>
<u>First, let's get the value of the first term:</u>
- aₙ = a + (n-1)d
- a₂₂ = a + 21d
- 149 = a + 21*7
- a = 149 - 147
- a= 2
<u>Next, let's find the sum of the first 20 terms</u>
- Sₙ = 1/2n(2a+ (n-1)d)
- S₂₀ = 1/2*20(2*2 + 19*7) = 10(4 + 133) = 10*137 = 1370
<u>Answer is</u> 1370
The first one in incorrect , it should be 130 but the rest are correct !
For the answer to the question above, If you've noticed, the statement mentioned "a number". Let's assign x to be the number. The first statement is twice a number (2x). Then, decreased by the quotient of that number and 2 (-x/2). Lastly, the statement at least 12 is written as >12.
So the answer is
2x - (x/2) >12
Answer:
1.
y = 20(11) + 300 = 520
y = 5(11)(11) = 605
y = 10(1.4)^11 = 404.96
hence the quadratic formula - y = 5x^2 has the largest y-value
2.
y = 20 (14) + 300 = 580
y = 5 (14) (14) = 980
y = 10(1.4)^ 14 = 1111.20 > this is greater than both equations above
14 is the smallest value of x for which the value of the exponential equation is greater than the values of both the linear and quadratic functions
Step-by-step explanation:
Draw two lines that connect at one point. label where they connect w and the other two ends j