What is Y-3x=-2 and Y+x=-6
2 answers:
Rearranging the first equation gives:
![y=3x-2](https://tex.z-dn.net/?f=y%3D3x-2)
Substituting this into the other equation gives:
![y+x=-6 \\(3x-2)+x=-6 \\4x-2=-6 \\4x=-4 \\x=-1](https://tex.z-dn.net/?f=y%2Bx%3D-6%0A%5C%5C%283x-2%29%2Bx%3D-6%0A%5C%5C4x-2%3D-6%0A%5C%5C4x%3D-4%20%5C%5Cx%3D-1)
If x=-1:
![y+(-1)=-6 \\y=-5](https://tex.z-dn.net/?f=y%2B%28-1%29%3D-6%0A%5C%5Cy%3D-5)
So
x=-1, y=-5
Y - 3x = -2 ⇒ 2y - 6x = -4
y + x = -6 ⇒ <u>2y + 2x = -12</u>
-<u>8x</u> = <u>8</u>
-8 -8
x = -1
y - 3(-1) = -2
y + 3 = -2
<u> -3 -3</u>
y = -5
(x, y) = (-1, -5)
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Use BODMAS rule,
where:
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simplify exponent
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![\rightarrow \sf -\dfrac{1}{5} \times [\:4-\(\dfrac{7}{8}]](https://tex.z-dn.net/?f=%5Crightarrow%20%5Csf%20-%5Cdfrac%7B1%7D%7B5%7D%20%5Ctimes%20%5B%5C%3A4-%5C%28%5Cdfrac%7B7%7D%7B8%7D%5D)
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multiply fractions
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Answer:
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Step-by-step explanation:
Look at the image below ↓
Its the metric system thats the problem