All categories

2 years ago

Anwser: 36÷(1-9×1-4)+1+2

2 answers:

5 0

So this is a BIDMAS question so first you do what’s in the brackets so you have (1-9x1-4) and you have to do the multiplication first out of that to get (1-9-4) which is -12 so then you have overall 36 / -12 + 1 + 2 so you have to do the division first so do 36/-12 to get -3 and you have -3 + 1 + 2 which is 0 so your answer is 0.

Karo-lina-s [1.5K]2 years ago

4 0

Answer:

The answer would be 0.

Step-by-step explanation:

(1 - 9 × 1 - 4) = - 12

36 ÷ - 12 = - 3

- 3 + 1 = - 2

- 2 + 2 = 0

Hope this helps!

You might be interested in

WHAT IS 14x-23=4x+1<br> PLEASE I NEED HELP ASAP!!

allsm [11]

Answer:

Step-by-step explanation:

Well if you want the answers there are 3 different ways

x = 12/5

x = 2.4

5 0

2 years ago

FIRST GETS BRAINIEST Michael finds that 35 customers at his grandfather's grocery store use a coupon. To simulate the behavior o

Andrei [34K]

There were 5 of the 15 in the simulation that used a coupon. To find the probability you just divide 5 by 15

P(=>4) = 5/15 = 1/3 - probability of 4 or more

3 0

3 years ago

Read 2 more answers

How do I solve all this

Cerrena [4.2K]

Number five is .45 repeating

3 0

2 years ago

WILL GIVE BRAINLIEST

Alex

Answer:

Step-by-step explanation:

(3.14)(15*15)(315)=222548

5 0

3 years ago

Help I am very bad at math I need answers by tomorrow if you can help please do

d1i1m1o1n [39]

Answer:

Step-by-step explanation:

(a - b)(a +b) = a² - b²

1 - Sin² A = Cos² A

$LHS = \frac{1}{1- Sin A} + \frac{1}{1 + Sin A}\\\\= \frac{1*(1 + Sin A)}{(1- Sin A)(1 + Sin A)} + \frac{1*(1- Sin A)}{(1 + Sin A)(1- Sin A)}\\\\= \frac{1 + Sin A+ 1 - Sin A}{1^{2}- Sin^{2} A}\\\\= \frac{2}{1 - Sin^{2} A}\\\\= \frac{2}{Cos^{2} A}\\\\= 2 Sec^{2} A$

2) Sec² A - Tan² A = 1

$LHS = \frac{1}{Sec A - Tan A}\\\\=\frac{1*(Sec A + Tan A)}{(Sec A - Tan A)(Sec A + Tan A)}\\\\=\frac{Sec A + Tan A}{Sec^{2} A - Tan^{2} A}\\\\=\frac{Sec A + Tan A }{1}\\\\= Sec A + Tan A = RHS\\\\\\$

3) LHS = Cosec² A + Cot² A

= Cosec² A + Cosec² A - 1

= 2Cosec² A - 1 = RHS

$4) LHS = \frac{Sec A}{Cos A}- \frac{Tan A}{Cot A}\\\\ = Sec A*\frac{1}{Cos A}-Tan A*\frac{1}{Cot A}\\\\ = Sec A * Sec A - Tan A * Tan A\\\\= Sec^{2} A - Tan^{2} A \\\\= 1$

3 0

2 years ago