If 101 is given in base <em>b</em>, then in base 10 you have
For instance, if <em>b</em> = 2, then
101₂ = 2² + 1 = 5₁₀
If <em>b</em> = 3, then
101₃ = 3² + 1 = 9₁₀
If <em>b</em> = 4, then
101₄ = 4² + 1 = 17₁₀
The answer depends entirely on the base of the given number.
Answer:
Step-by-step explanation:
What they are asking for here is where the y-values are negative in interval format. Intervals are x things only, no y's allowed. So the interval of (-infinity, -3) indicates an x value of negative infinity to an x value of -3. The y's are negative from an x value of negative infinity to an x-value of -3, then again from an x value of almost -1 to an x value of almost positive 1. So your choice is the last one listed there.
Answer:
Step-by-step explanation:
![y=-x^2-12x-4\\\\y=-(x^2+12x)-4\\\\y=-(\underline{x^2+2\cdot x\cdot6+6^2}-6^2)-4\\\\y=-\left[(x+6)^2-36\right]-4\\\\y=-(x+6)^2+36-4\\\\\bold{\underline{y=-(x+6)^2+32}}](https://tex.z-dn.net/?f=y%3D-x%5E2-12x-4%5C%5C%5C%5Cy%3D-%28x%5E2%2B12x%29-4%5C%5C%5C%5Cy%3D-%28%5Cunderline%7Bx%5E2%2B2%5Ccdot%20x%5Ccdot6%2B6%5E2%7D-6%5E2%29-4%5C%5C%5C%5Cy%3D-%5Cleft%5B%28x%2B6%29%5E2-36%5Cright%5D-4%5C%5C%5C%5Cy%3D-%28x%2B6%29%5E2%2B36-4%5C%5C%5C%5C%5Cbold%7B%5Cunderline%7By%3D-%28x%2B6%29%5E2%2B32%7D%7D)
