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irinina [24]
4 years ago
12

Think I got it wrong . So does anyone know the answer to the two boxes

Mathematics
1 answer:
BartSMP [9]4 years ago
7 0
Look at point (-3,-1) on triangle I. The corresponding point on triangle II is (-4, 1). X moved 1 to the left, so a -1 will go in the box for x. Y moved up 2, so a 2 will go in the box for y.
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A business with market power can<span> raise prices without losing any customers to competitors.

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4 years ago
Which relationship describes angles 1 and 2?
Fudgin [204]

Answer:

2 and then 1

Step-by-step explanation: 1 is the slideing line that goes up to down and 2 is the angle that goes left & right (thats all i can exsplain sorry ;(      )

3 0
3 years ago
Decide whether the triangles are similar
Ne4ueva [31]

The first one

Similar - SSS theorem

second one

Similar - AAA theorem

last one

Similar - SAS theorem

5 0
3 years ago
Find two numbers given that their sum is 60 and
likoan [24]

Answer:

12 and 48

Step-by-step explanation:

let n be the larger number , then \frac{1}{4} n is the smaller number and their sum is

x + \frac{1}{4} x = 60 ( multiply through by 4 to clear the fraction )

4x + x = 240 , that is

5x = 240 ( divide both sides by 5 )

x = 48

smaller number = \frac{1}{4} × 48 = 12

The 2 numbers are 12 and 48

4 0
3 years ago
Read 2 more answers
Suppose that in a casino game the payout is a random variable X . If X is positive, you gain money, if negative, you lose.
Vanyuwa [196]

Answer:

the conditional probability that X = 1 , X = 2 and X = 3 is  0.7333 (73.33%) , 0.25 (25%) and 0.0167 (1.67%) respectively

Step-by-step explanation:

a player wins money when i>0 then defining event W= gain money , then

P(W) = p(i>0) = p(1)+p(2)+p(3)

then the conditional probability can be calculated through the theorem of Bayes

P(X=1/W)= P(X=1 ∩ W)/P(W)

where

P(X=1 ∩ W)= probability that the payout is 1 and earns money

P(X=1 / W)= probability that the payout is 1 given money was earned

then

P(X=1/W)= P(X=1 ∩ W)/P(W) = P(X=1) / P(W) = p(1) /[p(1)+p(2)+p(3)] = 11/40 /(11/40+3/32+1/160 ) = 0.7333 (73.33%)

similarly

P(X=2/W)=p(2) /[p(1)+p(2)+p(3)] = 3/32 /(11/40+3/32+1/160 ) = 0.25 (25%)

P(X=3/W)=p(2) /[p(1)+p(2)+p(3)] = 1/160 /(11/40+3/32+1/160 ) = 0.0167 (1.67%)

8 0
4 years ago
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