Question

Solve this using the quadratic formula. Show work 2x^2+7x−5=0

Answer 1

Multiply the numbers (2*2=4)
$=\frac{-7+\sqrt{7^2-4\cdot \:2\left(-5\right)}}{2\cdot \:2}$

Apply the rule 
$\sqrt{7^2+2\cdot \:4\cdot \:5}$

7^2 =49
$=\sqrt{49+2\cdot \:4\cdot \:5}$

Multiply
$\sqrt{49+40}$

Add
$\sqrt{89}$

$=\frac{-7-\sqrt{89}}{4}$

Final solution:
$x=\frac{-7+\sqrt{89}}{4},\:x=\frac{-7-\sqrt{89}}{4}$