1.<br> Complete these factor trees.<br> 30<br> N---<br> 2 x O<br> 2 xox

Someone please help due tonight

Alika [10]

0=$5
1=$7
2=$9
3=$11
4=$13
5=$15
6=$17

4 0

2 years ago

A car has a windshield wiper on the driver's side that has total arm length of 10 inches. It rotates

son4ous [18]

Answer:

75.44 Square Inches

Step-by-step explanation:

The diagram of the problem is produced and attached.

To determine the area of the cleaned sector:

Let the radius of the larger sector be R

Let the radius of the smaller sector be r

Area of the larger sector $=\frac{\theta}{360}X\pi R^2$

Area of the smaller sector $=\frac{\theta}{360}X\pi r^2$

Area of shaded part =Area of the larger sector-Area of the smaller sector

$=\frac{\theta}{360}X\pi R^2-\frac{\theta}{360}X\pi r^2\\=\frac{\theta \pi}{360}X (R^2- r^2)$

From the diagram, R=10 Inch, r=10-7=3 Inch, $\theta=95^\circ$

Therefore, Area of the sector cleaned

$=\frac{95 \pi}{360}X (10^2- 3^2)\\=75.44$ Square Inches$

7 0

3 years ago

PLEASE HELP ASAP -- WITH THE WORKK<br><br>50 points

MAXImum [283]

Part-A:-

$\\ \sf\longmapsto x^2+3x-70(4x-12)$

$\\ \sf\longmapsto 4x^2+12x-280-12x^2+36x+840$

$\\ \sf\longmapsto -8x^2+48x+560$

Now

$\\ \sf\longmapsto (f.g)(3)$

$\\ \sf\longmapsto -8(3)^2+48(3)+560$

$\\ \sf\longmapsto -72+144+560$

$\\ \sf\longmapsto 72+560$

$\\ \sf\longmapsto 632$

Part-B:-

$\\ \sf\longmapsto f(3)$

$\\ \sf\longmapsto (3)^2+3(3)-70$

$\\ \sf\longmapsto 9+9-70$

$\\ \sf\longmapsto 18-70$

$\\ \sf\longmapsto -52$

Now

$\\ \sf\longmapsto g(f(3))$

$\\ \sf\longmapsto g(-52)$

$\\ \sf\longmapsto 4(-52-3)$

$\\ \sf\longmapsto 4(-55)$

$\\ \sf\longmapsto -220$

Part:-C

$\\ \sf\longmapsto g(-2)$

$\\ \sf\longmapsto 4(-2-3)$

$\\ \sf\longmapsto 4(-5)$

$\\ \sf\longmapsto -20$

Now

$\\ \sf\longmapsto f(g(-2))$

$\\ \sf\longmapsto f(-20)$

$\\ \sf\longmapsto (-20)^2+3(-20)-70$

$\\ \sf\longmapsto 400-60-70$

$\\ \sf\longmapsto 400-130$

$\\ \sf\longmapsto 270$

Part-D:-

g×f=f×g

$\\ \sf\longmapsto (g.f)(-2)$

$\\ \sf\longmapsto -8(-2)^2+48(-2)+560$

$\\ \sf\longmapsto 32-96+560$

$\\ \sf\longmapsto -64+560$

$\\ \sf\longmapsto 496$

6 0

2 years ago

What are two equivalent forms for the polynomial 3x - 2x -2x? How do you get them?

Lynna [10]

Simplify 3x -2x -2x = 3x + -2x + -2x
Combine like terms: 3x + -2x + -2x = (3x + -2x +-2x) = -x
answer is: -x

5 0

3 years ago

Find the area of a circle with radius 5mm, rounded to the nearest tenth. A. 15.7mm2 B. 31.4mm2 C. 78.5mm2 D. 246.7mm2

icang [17]

1. The Formula to getting the area of a circle is pi r^2= 3.14 times the radius squared. Plug in the number given in the question to get your answer.
2. The Circumference formula is 2pir which is 2 time 3.14 times the radius given. Plug in the number to get your answer.
3. This one is giving you the diameter, therefore you need to divide the diameter by 2 to get the radius (diameter is twice the size of radius) and plug in the radius into the first formula (3.14 times r^2) to get your answer.

8 0

2 years ago

1. Complete these factor trees. 30 N--- 2 x O 2 xox