The general equation for a line in the case where the slope and one point on the line are known is y-b = m(x-a), where m is the slope and (a,b) is the point.

Here f(4) = 3 corresponds to the point (4,3), and f '(4) = 2 corresponds to the slope of the tangent line at that point.

Thus the equation of the tangent line here is

y - 3 = 2(x - 4).

An alternative form of this equation would be y = 3 + 2x - 8, or

y = 2x - 5

3 0

3 years ago

The graph of a function f(x) passes through the following points: (0,0), (1, -2), (2,0) Which of the following could be f(x)?

Sveta_85 [38]

Answer:

f(x)= 2x^2-4x

Step-by-step explanation:

3 0

3 years ago

(201)3 is equivalente to: (11)10; (10010)2; (11)16; (23)8

sashaice [31]

$(201)_3=2\cdot3^2+0\cdot3^1+1\cdot3^0=2\cdot9+0\cdot3+1\cdot1=18+1=\boxed{(19)_{10}}$

Answers:

A) No

$(11)_{10}\neq(19)_{10}$

B) No

$(10010)_2=1\cdot2^4+0\cdot2^3+0\cdot2^2+1\cdot2^1+0\cdot2^0=16+0+0+2+0=\\\\=\boxed{(18)_{10}\neq(19)_{10}}$

C) No

$(11)_{16}=1\cdot16^1+1\cdot16^0=16+1=\boxed{(17)_{10}\neq(19)_{10}}$

D) Yes

$(23)_8=2\cdot8^1+3\cdot8^0=16+3=\boxed{(19)_{10}}$

7 0

3 years ago