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4 years ago

If you graph 2y+8=6x^2-10x what will be the y intercept?

Mathematics

1 answer:

Rufina [12.5K]4 years ago

8 0

Answer:

Y intercept will be -4.

Step-by-step explanation:

Here we are given our function as

$2y+8=6x^2-10x$

We are asked to determine the y intercept.

The y intercept is the y ordinate of the coordinates of the point at which the graph of the function intersects the y axis.

Please note that the point at which graph cuts the y axis have x=0

Hence in order to determine y intercept we need to put x=0 in our function and solve it for y :

$2y+8=6x^2-10x2y+8=6x^2-10x$

Putting x =0

$2y+8=6x^2-10x2y+8=6(0)^2-10(0)$

$2y+8=6x^2-10x2y+8=0-10(0)$

$2y+8=6x^2-10x2y+8=0$

subtracting both sides by 8

$2y+8=6x^2-10x2y=-8$

dividing both sides by 2

=-4

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A rectangular field has dimension of 91 feet by 60 and 1/3 feet what is the area of the field

Oliga [24]

Answer:

Area = $91*\frac{181}{3}=5490\frac{1}{3}$ square feet

Step-by-step explanation:

The area of a rectangle is given by the formula:

A = length * width

Where length is 91 feet and width is $60\frac{1}{3}$ feet

Before we do the multiplication, we have to change the mixed number [width] into an improper fraction by using the rule shown below:

$a\frac{b}{c}=\frac{(a*c)+b}{c}$

Hence,

$60\frac{1}{3}=\frac{181}{3}$

So, the area is:

Area = $91*\frac{181}{3}=5490\frac{1}{3}$ square feet

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4 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

36% of 112= what because I’m so confused

Gennadij [26K]

Answer:

40.32

Step-by-step explanation:

112 ÷ 100 = 1.12

1.12 × 36 = 4.032

6 0

3 years ago

Determine the period of the following trigonometric function. y=4cos(8πx)

Diano4ka-milaya [45]

The period of y = 4 cos(8πx) is 2π/(8π) = 1/4, since

cos(x - 2π) = cos(x)

and if we replace x with 8πx, we get

cos(8πx - 2π) = cos(8πx)

and

8πx - 2π = 8π (x - 1/4)

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3 years ago

Write all functions that are symmetric about the y-axis. Choose from the following six circular functions. yequals=sine xsinx,

horsena [70]

Answer:

Hence the function only :

Secx and Cosx functions are symmetric about y-axis

And remaining functions are not symmetric about y-axis.

Step-by-step explanation:

Given:

Six circular function as :

y= sinx ,y=cosx , y=tanx, y= cotx ,y=secx y=cosecx

To Find:

Which functions are symmetric about the y-axis

Solution:

The function is said to be symmetric about the y-axis is given by

f(x)=f(-x)

Now

1)For y=sinx i.e. f(x)=sinx

So put x=-x

f(-x)=sin(-x)

=-sinx

Hence f(x)≠f(-x)

This function is not symmetric about y-axis

2)For y=cosx ,i.e. f(x)=cosx

put x=-x

f(-x)=cos(-x)...............(as value for x and -x cos value remain the same )

=cosx

hence f(x)=f(-x)

This function is symmetric to the y-axis

3)For y=tanx i.e f(x)=tanx

put x=-x

f(-x)=tan(-x)

=-tanx

Hence f(x)≠f(-x)

This function is not symmetric about y-axis

4)For y=cotx i.e. f(x)=cotx

Using above observation,

f(x)≠f(-x)

This is not symmetric about y-axis

5)For y=secx i.e f(x)=secx

f(x)=f(-x)

This function is symmetric about y-axis.

6) for y=cosecx

f(x)≠f(-x)

This function is not symmetric about y-axis

4 0

3 years ago