The quadratic equation cannonball’s path if it was launched with the same velocity, but from the ground instead would be given by:
<h3>What is the quadratic equation for the height of a projectile?</h3>
Considering the gravity, it is modeled by:
In which:
is the initial velocity.
is the initial height.
For this problem, we want:
- The same initial velocity, hence
.
- Launched from the ground, hence
.
Then, the equation is:
More can be learned about quadratic equations at brainly.com/question/24737967
Answer:
The second one
Step-by-step explanation:
The equation for volume is l*w*h
l=length
w=width
h=hight
All you have to do is find the answer multiplying all of the numbers together.
Hope this helps!
I kind-of need more specifics here. You didn't give any dimensions, but okay. So if you notice, from the side, any cone just looks like a regular old triangle. And we can treat it like one when trying to find the slant height. Ever heard of the Pythagorean theorem? a squared plus b squared = c squared. so in this case, the hypotenuse, or c-side, will be your slant height. take the square of the distance from the circle-base's center to the apex. add that to the square of the radius of the base. Find the square root (using your calculator) of that sum, and there's your answer.
Answer: 30/45=6/9
30 6
___=___
45 a
cross multiply
30a=270
divide both sides by 30
a=9
5.Answer=A
2 1/5=2 2/10
2 2/10+1 1/10=3 3/10
______________
Answer=-1
3/-5+(-4/10)=
3/-5-0.4
-0.6-0.4=-1
Answer:
Step-by-step explanation:
We need to find the solution to the following system of equations:
and 
By plugging the value of 'y' into the first equation we have that:
⇒ 
Solving for 'x' we have:
So, the solution to the system of equation is: (37.5, -30)
