Answer:
Mean track length for this rock specimen is between 10.463 and 13.537
Step-by-step explanation:
99% confidence interval for the mean track length for rock specimen can be calculated using the formula:
M±
where
- M is the average track length (12 μm) in the report
- t is the two tailed t-score in 99% confidence interval (2.977)
- s is the standard deviation of track lengths in the report (2 μm)
- N is the total number of tracks (15)
putting these numbers in the formula, we get confidence interval in 99% confidence as:
12±
=12±1.537
Therefore, mean track length for this rock specimen is between 10.463 and 13.537
Answer:
-2x
Step-by-step explanation:
The value of y from the diagram is 9
<h3>Similar shapes</h3>
From the given figure, the shapes are similar, using the similarity theorem of triangles, you ill have;
6/10 = y/15
Cross multiply
10y = 15* 10
10y = 90
y = 90/10
y = 9
Hence the value of y from the diagram is 9
Learn more on similar shapes here: brainly.com/question/2644832
Answer:
4 = 16,000
8 = 32,000
10 = 40,000
Step-by-step explanation:
4 x 4 = 16 then add the zeros and then you have 16,000. Same thing with 8. 4 x 8 = 32 then add the zeros. Also goes for 10. 4 x 10 = 40 then add the zeros.
Answer:
a:3,11
Step-by-step explanation:
