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Ksivusya [100]
3 years ago
11

5=-2n helpppppppppppppppppppppppppppppppppppppppppp

Mathematics
1 answer:
Alenkinab [10]3 years ago
8 0

Answer:

n=-5/2

Step-by-step explanation:

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Thirty percent of the fifth grade students in a large school district read below grade level. The distribution of sample proport
fredd [130]

Answer: 0.9088  

Step-by-step explanation:

Given : \mu=0.30

\sigma=0.045  

Let x be a random available that represents the proportion of students that reads below grade level .

Using z=\dfrac{x-\mu}{\sigma , for x= 0.36 , we have

z=\dfrac{0.36-0.30}{0.045}=1.33333

Using standard normal z-value table,

P-value = P(

P(z [Rounded yo the nearest 4 decimal places.]

Hence, the probability that a second sample would be selected with a proportion less than 0.36 = 0.9088  

7 0
3 years ago
CALC- limits<br> please show your method
gladu [14]
A. Factor the numerator as a difference of squares:

\displaystyle\lim_{x\to9}\frac{x-9}{\sqrt x-3}=\lim_{x\to9}\frac{(\sqrt x-3)(\sqrt x+3)}{\sqrt x-3}=\lim_{x\to9}(\sqrt x+3)=6

c. As x\to\infty, the contribution of the terms of degree less than 2 becomes negligible, which means we can write

\displaystyle\lim_{x\to\infty}\frac{4x^2-4x-8}{x^2-9}=\lim_{x\to\infty}\frac{4x^2}{x^2}=\lim_{x\to\infty}4=4

e. Let's first rewrite the root terms with rational exponents:

\displaystyle\lim_{x\to1}\frac{\sqrt[3]x-x}{\sqrt x-x}=\lim_{x\to1}\frac{x^{1/3}-x}{x^{1/2}-x}

Next we rationalize the numerator and denominator. We do so by recalling

(a-b)(a+b)=a^2-b^2
(a-b)(a^2+ab+b^2)=a^3-b^3

In particular,

(x^{1/3}-x)(x^{2/3}+x^{4/3}+x^2)=x-x^3
(x^{1/2}-x)(x^{1/2}+x)=x-x^2

so we have

\displaystyle\lim_{x\to1}\frac{x^{1/3}-x}{x^{1/2}-x}\cdot\frac{x^{2/3}+x^{4/3}+x^2}{x^{2/3}+x^{4/3}+x^2}\cdot\frac{x^{1/2}+x}{x^{1/2}+x}=\lim_{x\to1}\frac{x-x^3}{x-x^2}\cdot\frac{x^{1/2}+x}{x^{2/3}+x^{4/3}+x^2}

For x\neq0 and x\neq1, we can simplify the first term:

\dfrac{x-x^3}{x-x^2}=\dfrac{x(1-x^2)}{x(1-x)}=\dfrac{x(1-x)(1+x)}{x(1-x)}=1+x

So our limit becomes

\displaystyle\lim_{x\to1}\frac{(1+x)(x^{1/2}+x)}{x^{2/3}+x^{4/3}+x^2}=\frac{(1+1)(1+1)}{1+1+1}=\frac43
3 0
3 years ago
Why did he farmer’s daughter watch the lazy cows?
Sati [7]

Answer:

The farmers daughter watch the lazy cows because the farmers daughter liked to see the meat loaf.


4 0
3 years ago
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The function f(x)=g(x), where f(x)=2x-5 and g(x)=x^2-6. The table below shows the process of solving using successive approximat
valkas [14]

Answer:

The positive solution is 2.4.

Step-by-step explanation:

The given functions are

f(x)=2x-5

g(x)=x^2-6

It is given that

f(x)=g(x)

2x-5=x^2-6

0=x^2-6-2x+5

0=x^2-2x-1

The quadratic formula:

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

x=\frac{2\pm \sqrt{(2)^2-4(1)(-1)}}{2(1)}

x=\frac{2\pm \sqrt{8}}{2}

x=\frac{2\pm 2\sqrt{2}}{2}

x=\frac{2(1\pm \sqrt{2})}{2}

x=1\pm \sqrt{2}

x=2.4,-0.4

Therefore the positive solution is 2.4.

6 0
3 years ago
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A brand new car is $22,000 and its value depreciates 7% each year. How many years will it take for your car to be $10,000? Round
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.200 because 22,000 % by 7 is 1540 which you divide by 10,000

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