I want to Say A - I searched google and it said that Archaea has something called membrane lipid bonding, ( which is oils and fat ) I didn't see anything about nucleus, size, or cell wall.
Hope this helped!
Answer:
N = 187.55
Explanation:
Here you just need to replace the terms and clear the equation.
You already know that,
- First capture: 25 prairie dogs.
- First marked animals: 25 (the whole first capture)
You let these animals leave and then you made another capture.
- Second capture: 135 prairie dogs
- Already Marked animals: 18 (these 18 dogs were caught in the first capture and marked before releasing them)
To know the size of the prairie dogs population you just need to use the following equation and clear N, which is the value that you are looking for.
Number of individual marked in first catch/Total population size, N = Number of individual marked in 2nd catch / Total number of 2nd catch
- Number of individual marked in first catch = 25 dogs
- Total population size, N = this is what we want to know
- Number of individual marked in 2nd catch = 18 dogs
- Total number of 2nd catch = 135 dogs
So now, we need to replace terms
25 / N = 18 / 135
25 / N = 0.1333
N = 25 / 0.1333
N = 187.55
Complete question:
Imagine that a newly discovered, recessively inherited disease is expressed only in individuals with type O blood, although the disease and blood group are independently inherited.
A normal man with type A blood and a normal woman with type B blood have already had one child with the disease. The woman is now pregnant for a second time.
Assuming that both parents are heterozygous for the gene that causes the disease, what is the probability that the second child will also have the disease? Express your answer as a fraction using the slash symbol and no spaces (for example, 1/2).
Answer:
The probability that the second child will also have the disease is 1/16.
Explanation:
<u>Available data:</u>
- Two genes independently inherited: one for blood type, the other for disease
- Man with type A blood x Woman with type B blood
- Both parents are heterozygous for the gene that causes the disease; Dd
If the man has A blood, and the woman has B blood, and they already have an affected child, this means that they must be heterozygous for blood type too.
Cross:
Parentals) AiDd x BiDd
Gametes) AD Ad iD id BD Bd iD id
Punnett square) AD Ad iD id
BD ABDD ABDd BiDD BiDd
Bd ABDd ABdd BiDd Bidd
iD AiDD AiDd iiDD iiDd
id AiDd Aidd iiDd iidd
F1) <u>Genotype</u>:
1/16 ABDD
2/16 ABDd
1/16 ABdd
1/16 AiDD
1/16 BiDD
2/16 AiDd
2/16 BiDd
1/16 Aidd
1/16 Bidd
1/16 iiDD
2/16 iiDd
1/16 iidd
<u>Phenotype:</u>
3/16 A/B normal
4/16 A normal
4/16 B normal
3/16 0 normal
1/16 0 affected by the disease.
Hi. excuse me sorry but i cant see your question. do you think you could post it again, please?
thank you
the answer is the beetle is neither harmed nor helped by the mite.
