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Doss [256]
4 years ago
11

What is the y-intercept? Give explanation, please.

Mathematics
1 answer:
vlada-n [284]4 years ago
4 0

Answer:

y = \frac{4}{5}x - 2 → y = \frac{4}{5}x + -2 \\ \\ -2 = b

Step-by-step explanation:

First, check the <em>rate of</em><em> </em><em>change</em><em> </em>[<em>slope</em>]:

\frac{-y_1 + y_2}{-x_1 + x_2} = m

\frac{-2 + 6}{-5 + 10} = \frac{4}{5}☑

Then plug these coordinates into the Slope-Intercept Formula instead of the <em>Point-Slope </em><em>Formula</em>, to get it done much swiftly. It does not matter which ordered pair you choose:

6 = ⅘[10] + b

8

−2 = b

y = \frac{4}{5}x - 2

_______________________________________________

2 = ⅘[5] + b

4

−2 = b

y = \frac{4}{5}x - 2

** You see? I told you it did not matter which ordered pair you choose because you will ALWAYS get the exact same result.

I am joyous to assist you anytime.

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tresset_1 [31]
The sum of the terms of a geometric sequence with common ratio lesser than 1 is calculated through the equation,

                                  Sn = (a1) x (1 - r^n) / (1 - r)
Substituting the known values,
                                 S5 = (6) x (1 - (1/3)^5) / (1 - 1/3) = 242/27
Thus, the sum of the first five terms is approximately equal to 8.96. 

6 0
3 years ago
Read 2 more answers
Write an equation of a parabola that passes through (3,-30) and has x-intercepts of -2 and 18. Then find the average rate of cha
Nookie1986 [14]

Answer:

The equation of the parabola is y = \frac{2}{5}\cdot x^{2}-\frac{32}{5}\cdot x -\frac{72}{5}.  The average rate of change of the parabola is -4.

Step-by-step explanation:

We must remember that a parabola is represented by a quadratic function, which can be formed by knowing three different points. A quadratic function is standard form is represented by:

y = a\cdot x^{2}+b\cdot x + c

Where:

x - Independent variable, dimensionless.

y - Dependent variable, dimensionless.

a, b, c - Coefficients, dimensionless.

If we know that (3, -30), (-2, 0) and (18, 0) are part of the parabola, the following linear system of equations is formed:

9\cdot a +3\cdot b + c = -30

4\cdot a -2\cdot b +c = 0

324\cdot a +18\cdot b + c = 0

This system can be solved both by algebraic means (substitution, elimination, equalization, determinant) and by numerical methods. The solution of the linear system is:

a = \frac{2}{5}, b = -\frac{32}{5}, c = -\frac{72}{5}.

The equation of the parabola is y = \frac{2}{5}\cdot x^{2}-\frac{32}{5}\cdot x -\frac{72}{5}.

Now, we calculate the average rate of change (r), dimensionless, between x = -2 and x = 8 by using the formula of secant line slope:

r = \frac{y(8)-y(-2)}{8-(-2)}

r = \frac{y(8)-y(-2)}{10}

x = -2

y = \frac{2}{5}\cdot (-2)^{2}-\frac{32}{5}\cdot (-2)-\frac{72}{5}

y(-2) = 0

x = 8

y = \frac{2}{5}\cdot (8)^{2}-\frac{32}{5}\cdot (8)-\frac{72}{5}

y(8) = -40

r = \frac{-40-0}{10}

r = -4

The average rate of change of the parabola is -4.

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Differentiate the function.

d

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x

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,

5

]

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