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3 years ago

What is the sum of the first five terms of a geometric series with a1 = 6 and r = 1/3?

Mathematics

2 answers:

kakasveta [241]3 years ago

8 0

Answer:

242/27

Step-by-step explanation:

tresset_1 [31]3 years ago

6 0

The sum of the terms of a geometric sequence with common ratio lesser than 1 is calculated through the equation,

Sn = (a1) x (1 - r^n) / (1 - r)
Substituting the known values,
S5 = (6) x (1 - (1/3)^5) / (1 - 1/3) = 242/27
Thus, the sum of the first five terms is approximately equal to 8.96.

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Answer:

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Step-by-step explanation:

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3 years ago

Find the slope and y-intercept of the graph of the equation.

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Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

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melamori03 [73]

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3 years ago

What is the domain and range of the relation shown in the table?

TEA [102]

Answer:

domain: {10,15,19,32}

range:{5,9,-1}

Step-by-step explanation:

As we know domain is the values of input and range is the values of output.

Here , x is the input and y is the output.

$\left[\begin{array}{cc}x&y\\10&5\\15&9\\19&-1\\32&5\end{array}\right]$

Thus the input values according to the given problem is : 10 ,15 , 19, and thus ,

⇒The domain would accordingly be these four numbers : 10 , 15 , 19 , 32.

Note that we donot have any information regarding the other values of x.

The range is : { 5,9,-1 } only as the 5 is repeated in two cases .

Range is unique and there must be not repetition. Thus the apt answer would be :

domain: {10,15,19,32}

range:{5,9,-1}

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3 years ago