Answer:
If a<b, x<2
If a>b, x>2
Step-by-step explanation:
ax-bx>2a-2b, (a-b)x>2(a-b)
If a>b, x>2(a-b)/(a-b)=2
If a<b, x<2(a-b)/(a-b)=2
The answer to the question
9514 1404 393
Answer:
yes
Step-by-step explanation:
The figure can be shown to be a parallelogram by showing the sum of endpoints of the diagonals is the same.
A +C = B +D
(0, 6) +(0, -4) = (0, 2) = (3, 5) +(-3, -3) . . . . diagonals bisect each other
If the diagonals of a quadrilateral bisect each other, it is a parallelogram. A parallelogram with a right angle is a rectangle. So, ABCD is a rectangle.
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<em>Additional comment</em>
The midpoint of each diagonal is half the sum of the end point coordinates. That is, the midpoints are (0, 2)/2 = (0, 1). Since calculation of the midpoints requires both sums be divided by 2, we can tell the midpoints are the same if the sums are the same.
Answer:
n+7=17
n=17-7
n=10
Step-by-step explanation: