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Black_prince [1.1K]
3 years ago
8

Sophia is dilating a figure. One of her pre-image points with coordinates (-3, 5) has an image with coordinates (-9, 15). If one

of the other image points has coordinates (3, 1), what are the coordinates of its pre-image point?
Mathematics
2 answers:
Galina-37 [17]3 years ago
8 0
The dilation factor Sophia is using appears to be
  (image coordinate)/(original coordinate) = -9/-3 = 15/5 = 3

Then the problem tells us
  (pre-image point)×3 = (3, 1)
so we conclude
  (pre-image point) = (3, 1)/3 = (1, 1/3)
son4ous [18]3 years ago
8 0

Answer:

(1, 1/3)

> To get from (-3, 5) to (-9, 15) you do x3 to x & y

> 3 is the scale factor

> To figure out the pre-image point, you divide x & y by 3

> Therefore, (1, 1/3) is the answer

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What is 2-1+5×4×11 order of operation ​
Alenkasestr [34]

Answer:

221

Step-by-step explanation:

2 - 1 + 5 · 4 · 11 = 2 - 1 + 20 · 11  = 2 - 1 + 220

2 - 1 + 220 = 1 + 220

7 0
3 years ago
x^2-8x+15=0 solve the equation by completing the square. Round your solutions to the nearest hundredth, if necessary.
zaharov [31]

Answer:

x = 3, 5

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtract Property of Equality

<u>Algebra I</u>

  • Terms/Coefficients/Degrees
  • Standard Form: ax² + bx + c = 0
  • Multiple Roots
  • Factoring
  • Completing the Square: -b/(2a)

Step-by-step explanation:

<u>Step 1: Define</u>

x² - 8x + 15 = 0

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. [Subtraction Property of Equality] Subtract 15 on both sides:                     x² - 8x = -15
  2. Complete the Square [Addition Property of Equality]:                                 x² - 8x + 16 = -15 + 16
  3. [Complete the Square] Simplify:                                                                   (x - 4)² = 1
  4. [Equality Property] Square root both sides:                                                  x - 4 = ±1
  5. [Addition Property of Equality] Add 4 on both sides:                                   x = 4 ± 1
  6. Evaluate:                                                                                                          x = 3, 5
7 0
3 years ago
Find the area of the shaded region for the given figure in terms of x.
Vlada [557]

Answer:

Area of the shaded region = (6x + 3)

Step-by-step explanation:

Area of the shaded region = Area of the large rectangle - Area of the small rectangle

Area of the large rectangle = Length × Width

                                             = (x + 2)(x + 2)

                                             = (x + 2)²

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Area of the small rectangle = (x - 1)(x - 1)

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Area of the shaded region  = (x² + 4x + 4) - (x² - 2x + 1)

                                             = 6x + 3

Area of the shaded region = (6x + 3)

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