NEED HELP ASAP!!!!!!!!

Mathematics

1 answer:

Ymorist [56]3 years ago

5 0

<span>Segment EG is half the length of segment BH because of the Midsegment theorem</span>

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PLS HELP WHAT ARE THESE TWO ILL GIVE BRAINLESS AND SHOW UR WORK

Hitman42 [59]

Answer:

2) C

3) 62 degrees

Step-by-step explanation:

72+46=118

180-118

Hope this helps

3 0

3 years ago

Which pair of expressions has equivalent values? 1 Superscript 13 and 1 Superscript 15 6 Superscript 1 and 9 Superscript 1 7 Sup

lora16 [44]

Answer:

1 Superscript 13 and 1 Superscript 15

Step-by-step explanation:

The process of exponentiation can be mathematically written as:

a^b

where a is called the base, and b is called the exponent.

Basically it means that we have to multiply the base with itself as many times as the value of the exponent.

For example 2^4 is 2•2•2•2

Having this in mind, 1^13 and 1^15 have equivalent values, because no matter how many times we multiply 1 with itself it will always be equal to 1.

8 0

4 years ago

Read 2 more answers

I need help with this problem.

sdas [7]

Answer:

$\text{4}\quad -3x^{-1}+x^{-2}$

Step-by-step explanation:

The answer choices suggest there is a common factor of (x+2) that can be removed from numerator and denominator.

The denominator factors as ...

$x^3+2x^2=x^2(x+2)$

The numerator obviously has no factors of x. We can try any of several means to determine if (x+2) is a factor. I tried synthetic division and found that the numerator can be written as ...

$-3x^2-5x+2=(-3x+1)(x+2)$

Then the expression simplifies to ...

$\dfrac{-3x^2-5x+2}{x^3+2x^2}=\dfrac{(-3x+1)(x+2)}{x^2(x+2)}\\\\=\dfrac{-3x+1}{x^2}=\dfrac{-3x}{x^2}+\dfrac{1}{x^2}=-3x^{-1}+x^{-2} \qquad\text{matches choice 4}$