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aleksley [76]
2 years ago
6

CAN SOMEONE HELP ME PLEASE?

Biology
1 answer:
GREYUIT [131]2 years ago
6 0
A. Is the correct answer :)
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butalik [34]
Which picture?, pls Clip the picture for the answer.
8 0
3 years ago
Why do you think people like Ben Saunders explore extreme environments? Do you think you’d like to explore an extreme environmen
adell [148]

One major reason for exploring extreme environments is to find new resources. An example of a resource is the search for a new antibiotic. Extreme environments have rare species endemic to the regions which can offer different insights from the normative environment we are used to.

No, I would not. This is because the risk of death is higher in an extreme environment. Example of these risks are deadly diseases or harsh climate. The body may be unable to adjust to the extreme environment hence may be unable to restore homoeostasis;  such as in restoring body heat in extremely cold environments hence leading to hypothermia.  

7 0
3 years ago
What is the relationship between air pressure and wind velocity?
Pachacha [2.7K]

Explanation:

Velocity refers to how fast the air is moving in distance per unit of time. While pressure is the measure of force applied on an area.

7 0
2 years ago
g If a person takes a prescribed dose of 10 milligrams of Valium, the amount of Valium in that person's bloodstream at any time
Elenna [48]

Answer:

a. 8.1 milligrams

b. 40.07 hours

c. 8.859 milligrams

Explanation:

If a person takes a prescribed dose of 10 milligrams of Valium, the amount of Valium in that person's bloodstream at any time can be modeled by

A_{t}=10e^{-0.0173t}

Where A(t) = amount of Valium remaining in the blood after t hours

t = time or duration after the drug is taken

a. we have to calculate the amount of drug remaining in the bloodstream after 12 hours

A_{12}=10e^{-0.0173\times12}

A_{12}=10e^{-0.2076}

                = 10×0.81253

                = 8.1 milligrams

b. In this part we have to calculate the time when A(t) = 5 milligrams

5=10e^{-0.0173\timest}

\frac{5}{10}=e^{-0.0173t}

0.5 = e^{-0.0173t}

Now we take natural log on both the sides of the equation.

ln(0.5) = ln(e^{-0.0173t})

-0.69314 = -0.0173t

t = \frac{0.69314}{0.0173}

t = 40.0658

 ≈ 40.07 hours

c. In this part we have to calculate the rate, by which amount of drug will decay in the bloodstream after 7 hours.

A_{7}=10e^{-0.0173\times7}

A_{7}=10e^{-0.1211}

              = 10×0.8859

              = 8.859 milligrams

6 0
3 years ago
According to the oxygen-hemoglobin dissociation curve, PO2 in the lungs of 100 mm Hg results in Hb being 98% saturated. At high
tatiyna

Answer:

95%.

Explanation:

Oxygen-hemoglobin dissociation curve:

Oxygen-hemoglobin dissociation curve is basically a sigmoid curve which relates between the saturation of oxygen (SO2) and partial pressure of oxygen in blood (PO2). It shows the affinity of oxygen with hemoglobin at different temperature and other factors. In the oxygen-hemoglobin dissociation curve; saturated oxygen is ploted on verticle axis and partial pressure of oxygen in mmHg on the horizontal axis.

Here in the above scenario at the high altitude oxygen is less and at 80 mmHg, Hb would be 95% saturated.

8 0
2 years ago
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