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IrinaK [193]
3 years ago
11

Assume that Delalo, Inc. is operating at full capacity. Also assume that assets, costs, and current liabilities vary directly wi

th sales. The dividend payout ratio is constant. What is the external financing needed if sales increase by 10 percent?
Business
2 answers:
Murrr4er [49]3 years ago
6 0

Answer:

Explanation:

External financing needed =

(1.10×$12,470) - (1.10× $1330)- $3200-$4600 - ($2,840+($45×1.10)=$616. 36.

The need for external financing is intermediate.

son4ous [18]3 years ago
6 0

Answer:

External Financing Needed (EFN) = $616.36

Explanation:

This question didn't give full information of the balance sheet.

The following are needed to find find the EFN:

- Sales

-Income

-Taxable Income

-Net Income

-Taxes

Nevertheless, here is the calculation:

External financing needed =

(1.10×$12,470) - (1.10× $1330)- $3200-$4600 - ($2,840+($45×1.10)=$616. 36

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Suppose that video game discs are a normal good. If the incomeof video game players increase, you predict that in the market for
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3 years ago
Elizabeth Kennedy sells beauty supplies. Her annual demand for a particular skin sparkle is 17,000 units. The cost of placing an
elena-s [515]

Answer:

The minimum cost will be "$214085".

Explanation:

D = 1700 units \\\\S =  \$ 50 \\\\H=  20%\\

i) When quantity = 1-1500,  price = $ 12.50 , and holding price is $12.50 * 20 %= $2.50.

ii) When quantity = 1501 -10,000,  price = $ 12.45 , and holding price is $12.45 * 20 %= $2.49.

iii) When quantity = 10,0001- and more,  price = $ 12.40 , and holding price is $12.40 * 20 %= $2.48.

EOQ= \sqrt{\frac{2DS}{H}} \\\\EOQ1= \sqrt{\frac{2\times 17000\times 50}{2.50}} \\\\EOQ1=824.62 \ \ \ or \ \ \ 825\\

EOQ2= \sqrt{\frac{2\times 17000\times 50}{2.49}} \\\\EOQ1=826.2T \ \ \ or \ \ \ 826\\

EOQ3= \sqrt{\frac{2\times 17000\times 50}{2.48}} \\\\EOQ3=827.93 \ \ \ or \ \ \ 828\\

know we should calculate the total cost of EOQ1 and break ever points (1501 to 10,000)units

total \ cost = odering \ cost + holding \ cost + \ Annual \ product \ cost\\\\total_c  = \frac{D}{Q} \times S +  \frac{Q}{2} \times H + (p \times D) \\\\T_c  = \frac{17000}{825} \times 50+  \frac{825}{2} \times 2.50 + (12.50 \times 17000)\\\\T_c = 1030 .30 +1031.25+212500\\\\T_c =$ 214561.55\\\\

T_c  = \frac{17000}{1501} \times 50+  \frac{1501}{2} \times 2.49 + (12.45 \times 17000)\\\\T_c = 566.28 +1868.74+211650\\\\T_c =$ 214085.02 \ \ \ or \ \ \  $ 214085\\\\

T_c  = \frac{17000}{10001} \times 50+  \frac{10001}{2} \times 2.48 + (12.40 \times 17000)\\\\T_c = 84.99+ 12401.24+210800\\\\T_c =$ 223286.23 \\

The total cost is less then 15001. So, optimal order quantity is 1501, that's why cost is = $214085.

5 0
3 years ago
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