D!! It’s super easy I hope you can learn how to do it
Answer:
The answer is B) 0.57.
Step-by-step explanation:
In this problem we have to apply queueing theory.
It is a single server queueing problem.
The arrival rate is
and the service rate is
.
The proportion of time that the server is busy is now as the "server utilization"and can be calculated as:

where c is the number of server (in this case, one server).
X = number of singles matches
y = number of doubles mnathes
so we have the equation x + y = 13.......(1)
also
2x + 4y = 38 ...........(2)
(1) and (2) are the required equations
b) Find how many maches are in progress by solivng the above equations:-
x + y = 13 multiply this by -2:-
-2x - 2y = -26
2x + 4y = 38 Adding to removes the terms in x:-
2y = 12
y = 6
so x = 13-6 = 7
So the answer is 6 double matches and 7 singles are in progress.
The answer would be 8,107