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pantera1 [17]
3 years ago
12

How many diagnols can fit in a 8 sided shape?

Mathematics
1 answer:
Jobisdone [24]3 years ago
8 0

Drawing a diagonal means to connect a vertex with another non-adjacent vertex.

So, for each vertex, we have 8-3=5 possible diagonals. This leads to a total of 8*5=40 diagonals.

We have to divide this number by 2 though, because in this way we're counting each diagonal twice (connecting points AB or BA gives the same diagonal).

So, an 8 sided shape has 20 diagonals.

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enot [183]

Answer:

d. AAS

Step-by-step explanation:

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6 0
3 years ago
Is this a function graph
Nesterboy [21]

Answer:

No

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3 years ago
Find the value of t in the diagram
12345 [234]

In a trapezoid, with bases b and B and height h, the area is given by


A = \frac{(B+b)h}{2}


In your case:


B = BC = 3t

b = AD = t

h = AB = t


so, the formula becomes


A = \frac{(3t+t)t}{2} = \frac{4t^2}{2} = 2t^2


Since the area is 50 \text{cm}^2, we have


2t^2 = 50 \iff t^2 = 25 \iff t = 5

5 0
3 years ago
Read 2 more answers
Help! 144/360 reduced using prime factorization
kicyunya [14]
Divdie by 12
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7 0
3 years ago
Can someone help me please?
kupik [55]
3/10=0.3=30%

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4/10=0.4=40%
5 0
3 years ago
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