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nekit [7.7K]
3 years ago
9

What is 3x-2x equal to

Mathematics
1 answer:
Damm [24]3 years ago
5 0
3x-2x=1x
Since they are numbers of the same variable thus they can be added or subtracted.
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(5.6x - 4) + (16 - 2.1x)<br><br> What is the sum of this expression?
Damm [24]

\huge\text{Hey there!}

\large\textsf{(5.6x - 4) + (16 - 2.1x)}

\large\text{DROP the PARENTHESES}

\large\textsf{5.6x - 4 + 16 - 2.1x}

\large\text{COMBINE the LIKE TERMS}

\large\textsf{5.6x - 2.1x - 4 + 16}

\large\textsf{5.6x - 2.1x = \bf  3.5x}

\large\textsf{-4 + 16 = \bf  12}

\large\textsf{=  \bf 3.5x + 12 }

\boxed{\boxed{\large\text{Answer: \huge \bf 3.5x + 12}}}\huge\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

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3 years ago
Find the slope of the line that goes through (1, 3) and (-2,-6).
monitta

Answer:

m= -3

Step-by-step explanation:

slope intercept formula

(y2-y1)/ (x2-x1)

-6-3= -9

-2-1=-3

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3 0
4 years ago
Graph the inequalitly y&gt; 2/3x -1
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Frank wants to build a garden with the dimensions below.
dexar [7]
Given:
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Width = 2 + x 

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Perimeter = 2(13 + 7)
Perimeter = 2(20)
Perimeter = 20 feet of fencing
7 0
3 years ago
Read 2 more answers
Let v1 =(-6,4) and v2=(-3,6) compute the following what i sthe angle between v1 and v2
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\bf ~~~~~~~~~~~~\textit{angle between two vectors }&#10;\\\\&#10;cos(\theta)=\cfrac{\stackrel{\textit{dot product}}{u \cdot v}}{\stackrel{\textit{magnitude product}}{||u||~||v||}} \implies &#10;\measuredangle \theta = cos^{-1}\left(\cfrac{u \cdot v}{||u||~||v||}\right)\\\\&#10;-------------------------------

\bf \begin{cases}&#10;v1=\ \textless \ -6,4\ \textgreater \ \\&#10;v2=\ \textless \ -3,6\ \textgreater \ \\&#10;------------\\&#10;v1\cdot v2=(-6\cdot -3)+(4\cdot 6)\\&#10;\qquad \qquad 42\\&#10;||v1||=\sqrt{(-6)^2+4^2}\\&#10;\qquad \sqrt{52}\\&#10;||v2||=\sqrt{(-3)^2+6^2}\\&#10;\qquad \sqrt{45}&#10;\end{cases}\implies \measuredangle \theta =cos^{-1}\left( \cfrac{42}{\sqrt{52}\cdot \sqrt{45}} \right)&#10;\\\\\\&#10;\measuredangle \theta =cos^{-1}\left(  \cfrac{42}{\sqrt{2340}} \right)\implies \measuredangle \theta \approx 29.74488129694^o
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3 years ago
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