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irakobra [83]
3 years ago
8

Oranges cost 25 cents for 1/2 kilograms. How much would 8 kilograms of oranges cost?

Mathematics
2 answers:
Elden [556K]3 years ago
8 0
Multiply both sides by two to get how many cents oranges cost per kilogram. If 50 cents = 1 kg of oranges, then 400 cents = 8 kg of oranges.
madreJ [45]3 years ago
7 0

Here we shall use the unitary method.

We shall first find the cost of 1 kg oranges and then find the cost of 8 kg ornages.

The fraction 1/2 = 0.5

Also 100 cents = $1

So 25 cents = 25/100 = $0.25

The cost of 0.5kg oranges = $0.25

Hence the cost of 1 kg oranges = 2 ×0.5kg shall be

= 2 ×0.25

= $0.50

So the cost of 8 kg oranges

= 8 × 0.50

= $4.00

The cost of 8 kg oranges at 25 cents for half kg shall be $4.00

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Is 373 a prime number
ArbitrLikvidat [17]
Yes 373 is in fact a prime number
3 0
3 years ago
Three times a number increased by 20, is 14 less than the product of five and the 1095
Zinaida [17]

3x + 20 = (5 \times 1095) - 14 \\ 3x + 20 = 5475 - 14 \\ 3x = 5461 - 20 \\ 3x = 5441 \\ x =  \frac{5441}{3}

8 0
2 years ago
What is the solution to the system of equations? Y=-3-2. 5x+2y=15
ivolga24 [154]

Answer:

x=-19

y=55

Step-by-step explanation:

y=-3x-2.

5x+2y=15

substitute y into 5x+2y =15

5x +2 (-3x-2) = 15

distribute

5x -6x-4 = 15

combine like terms

-x-4 =15

add 4 to each side

-x-4+4 = 15+4

-x=19

multiply by -1

x = -19

now lets find y

y= -3x-2

y = -3(-19) -2

y = 57-2

y =55



4 0
3 years ago
What is 1/4 of 1/2 ................................
jasenka [17]

Answer:

1/8

Step-by-step explanation:

When you are dividing by fractions you flip and multiply this also go's for when you multiply a fraction you flip and divide. what makes it easier is to put it in decimal form so 1/4 = .25 and 1/2 = .50 so what is 25/50? so it would come back to .125 which is equal to 1/8. If you are not very good at math just ignore this lol

5 0
3 years ago
Read 2 more answers
Given the rectangle abcd shown below has a total area of 72. E is in the midpoint of bc and f is the midpoint of dc. What is the
scoray [572]

Refer to the attached image.

Given the rectangle ABCD of length 'l' and height 'h'.

Therefore, CD=AB = 'l' and BC = AD = 'h'

We have to determine the area of triangle AEF.

Area of triangle AEF = Area of rectangle ABCD - Area of triangle ADF - Area of triangle ECF - Area of triangle ABE

Area of triangle ADF = \frac{1}{2}bh

= \frac{1}{2}(DF \times AD)

= \frac{1}{2}(\frac{l}{2} \times h)

=\frac{lh}{4}

Area of triangle ECF = \frac{1}{2}bh

= \frac{1}{2}(CF \times CE)

= \frac{1}{2}(\frac{l}{2} \times \frac{h}{2})

=\frac{lh}{8}

Area of triangle ABE = \frac{1}{2}bh

= \frac{1}{2}(AB \times BE)

= \frac{1}{2}(l \times \frac{h}{2})

=\frac{lh}{4}

Now, area of triangle AEF =

Area of rectangle ABCD - Area of triangle ADF - Area of triangle ECF - Area of triangle ABE

= 72 - (\frac{lh}{4} + \frac{lh}{8} + \frac{lh}{4})

= 72 - (\frac{2lh+lh+2lh}{8})

=72 - (\frac{5lh}{8})

=72 - (\frac{5 \times 72}{8})

=\frac{72 \times 8 - (5 \times 72)}{8}

= 27 units

Therefore, the area of triangle AEF is 27 units.

8 0
3 years ago
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