Think of A as a constant - with D it's 117 and with M it's 88
So the difference between D and M is 29 (117-88)
We also know that M + D = 161
Let's substitute in the problem We will leave M equal to M and rewrite D as M+29 since it is 29 kg heavier.
M + M + 29 -161 or 2M +29 = 161 Subtracting 29 from both sides we get 2M=122
Now divide both sides two and get M=61
Since D is M+29 it is 61+29 or 100kg
Finally A + M = 88 A + 61 - 88 Subtract 61 from both sides and get A=17
So there you have it:
A=17kg
M=61kg
D=100kg and it works in all three equation in your problem (try it to check)
Answer:
3 x 5= 15
Step-by-step explanation:
If you count by 5's like 5, 10, 15, 20
And if you count by 3's: 3, 6, 9, 12, 15
then find the least common multiple and it is 15
Please mark me as the Branlyest ;) Thanks
The answer is 28ft for this answer
Answer:
1960
Step-by-step explanation:
10x14=140
7+7=14
14x140=1960
Area=1960
Answer:
The given set of equation are: x+ (-45) ≤ 35 , x - (-45) ≥ 35
For the given equality to be true, x ≤ 35
Step-by-step explanation:
Here, given the first number = x
Second number = -45
Now, Sum of x and - 45 is at most 35.
⇒ x+ (-45) ≤ 35
Also, The difference of x and -45 is at least 35.
⇒ x - (-45) ≥ 35
Now, simplifying the given set of equations:
x - 45 ≤ 35 ⇒ -x - (-45) > - 35 ( as 3 < 4 ⇒ -3 > -4)
or, -x + 45 > - 35
and second equation is x + 45 ≥ 35
Now, solving both the equations by not taking sign of inequality in to the consideration, we get
x - 45 = 35
x + 45 = 35
Adding both equations,we get: ⇒ 2x = 70
or x = 35
Hence for the given equality to be true, x ≤ 35
