We know that
a1=1
a2=3
a3=9
a2/a1=3/1----> 3
a3/a2=9/3----> 3
<span>common ration r is equal to 3
number of terms n is 12
The </span><span>Sum of geometric series is given by the formula
</span>Sum=a1*[1-r<span>^n]/[1-r]
</span>Sum=1*[1-3^12]/[1-3]-----> Sum=[1-3^12]/[1-3]----> [3^12-1]/[3-1]
<span>Sum=531440/2-----> 265720
the answer is
265720
</span>
Positive add a positive plus positive equals positive neg plus neg equals neg
Answer:
70°
Step-by-step explanation:
Minor angle at the centre:
360 - 250 = 110
Two tangents make an angle of 90° each
90 + 90 + 110 + x = 360
x = 360 - 290
x = 70°
Answer: 90
Step-by-step explanation:
In the number 73,951, the digit 9 is on the third position, so you need to put the number of the position minus one zeros before it: ( position number 3, 3 - 1 = 2, so we put 2 zeros)
the 9 in that digit represents a 900.
now, 1/10 times that number is:
900*(1/10) = 900/10 = 90
then the answer is 90.
In the number 90, the value represented by the 9 is equal to 1./10 times the value represented by the 9 in 73,951
Step-by-step explanation:
4.5 s, 324 ft
Explanation:
The object is projected upward with an initial velocity of
v_0 = 144 ft/sv
0
=144ft/s
The equation that describes its height at time t is
s(t) = -16t^2 + 144 ts(t)=−16t
2
+144t (1)
where t, the time, is measured in seconds.
In order to find the time it takes for the object to reach the maximum height, we must find an expression for its velocity at time t, which can be found by calculating the derivative of the position, s(t):
v(t) = s'(t) = -32t +144v(t)=s
′
(t)=−32t+144 (2)
At the maximum heigth, the vertical velocity is zero:
v(t) = 0
Substituting into the equation above, we find the corresponding time at which the object reaches the maximum height:
\begin{gathered}0=-32t+144\\t=\frac{144}{32}=4.5 s\end{gathered}
0=−32t+144
t=
32
144
=4.5s
And by substituting this value into eq.(1), we also find the maximum height:
s(t) = -16(4.5)^2+144(4.5)=324 fts(t)=−16(4.5)
2
+144(4.5)=324ft
<h3>used this way i even don't know sorry:))</h3>
